Physics for Scientists and Engineers with Modern Physics
10th Edition
ISBN: 9781337553292
Author: Raymond A. Serway, John W. Jewett
Publisher: Cengage Learning
expand_more
expand_more
format_list_bulleted
Concept explainers
Question
Chapter 33, Problem 2P
(a)
To determine
The electric field the rod creates at the point
(b)
To determine
The magnetic field the rod creates at the point
(c)
To determine
The force exerted on an electron at point
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionChapter 33 Solutions
Physics for Scientists and Engineers with Modern Physics
Ch. 33.1 - Prob. 33.1QQCh. 33.3 - What is the phase difference between the...Ch. 33.3 - Prob. 33.3QQCh. 33.5 - Prob. 33.4QQCh. 33.6 - Prob. 33.5QQCh. 33.7 - Prob. 33.6QQCh. 33.7 - Prob. 33.7QQCh. 33 - Prob. 1PCh. 33 - Prob. 2PCh. 33 - Prob. 3P
Ch. 33 - Prob. 4PCh. 33 - The distance to the North Star, Polaris, is...Ch. 33 - Prob. 6PCh. 33 - Prob. 7PCh. 33 - Prob. 8PCh. 33 - Prob. 9PCh. 33 - Prob. 10PCh. 33 - Prob. 11PCh. 33 - Prob. 12PCh. 33 - If the intensity of sunlight at the Earths surface...Ch. 33 - Prob. 14PCh. 33 - Prob. 15PCh. 33 - Review. Model the electromagnetic wave in a...Ch. 33 - Prob. 17PCh. 33 - Prob. 18PCh. 33 - Prob. 19PCh. 33 - Prob. 20PCh. 33 - Prob. 21PCh. 33 - The intensity of sunlight at the Earths distance...Ch. 33 - Prob. 23PCh. 33 - Prob. 24PCh. 33 - Prob. 25PCh. 33 - Prob. 26PCh. 33 - Extremely low-frequency (ELF) waves that can...Ch. 33 - A large, flat sheet carries a uniformly...Ch. 33 - Prob. 29PCh. 33 - Prob. 30PCh. 33 - Prob. 31PCh. 33 - Prob. 32PCh. 33 - Prob. 33APCh. 33 - Prob. 34APCh. 33 - Prob. 35APCh. 33 - Prob. 36APCh. 33 - Prob. 37APCh. 33 - One goal of the Russian space program is to...Ch. 33 - Prob. 39APCh. 33 - Prob. 40APCh. 33 - Prob. 41APCh. 33 - Prob. 42APCh. 33 - Prob. 43APCh. 33 - Prob. 44APCh. 33 - Review. (a) A homeowner has a solar water heater...Ch. 33 - Prob. 46APCh. 33 - Prob. 47APCh. 33 - Prob. 48APCh. 33 - Prob. 49APCh. 33 - Prob. 50CPCh. 33 - Prob. 51CP
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- A magnetic field directed into the page changes with time according to B = 0.030 0t2 + 1.40, where B is in teslas and t is in seconds. The field has a circular cross section of radius R = 2.50 cm (see Fig. P23.28). When t = 3.00 s and r2 = 0.020 0 m, what are (a) the magnitude and (b) the direction of the electric field at point P2?arrow_forwardTwo infinitely long current-carrying wires run parallel in the xy plane and are each a distance d = 11.0 cm from the y axis (Fig. P30.83). The current in both wires is I = 5.00 A in the negative y direction. a. Draw a sketch of the magnetic field pattern in the xz plane due to the two wires. What is the magnitude of the magnetic field due to the two wires b. at the origin and c. as a function of z along the z axis, at x = y = 0? FIGURE P30.83arrow_forwardA long, straight, horizontal wire carries a left-to-right current of 20 A. If the wire is placed in a uniform magnetic field of magnitude 4.0105 T that is directed vertically downward, what is tire resultant magnitude of the magnetic field 20 cm above the wire? 20 cm below the wire?arrow_forward
- Calculate the magnitude of the magnetic field at a point 25.0 cm from a long, thin conductor carrying a current of 2.00 A.arrow_forwardOne long wire carries current 30.0 A to the left along the x axis. A second long wire carries current 50.0 A to the right along the line (y = 0.280 m, z = 0). (a) Where in the plane of the two wires is the total magnetic field equal to zero? (b) A particle with a charge of 2.00 C is moving with a velocity of 150iMm/s along the line (y = 0.100 m, z = 0). Calculate the vector magnetic force acting on the particle. (c) What If? A uniform electric field is applied to allow this particle to pass through this region undetected. Calculate the required vector electric field.arrow_forwardA wire 2.80 m in length carries a current of 5.00 A in a region where a uniform magnetic field has a magnitude of 0.390 T. Calculate the magnitude of the magnetic force on the wire assuming the angle between the magnetic field and the current is (a) 60.0, (b) 90.0, and (c) 120.arrow_forward
- Two long coaxial copper tubes, each of length L, are connected to a battery of voltage V. The inner tube has inner radius o and outer radius b, and the outer tube has inner radius c and outer radius d. The tubes are then disconnected from the battery and rotated in the same direction at angular speed of radians per second about their common axis. Find the magnetic field (a) at a point inside the space enclosed by the inner tube r d. (Hint: Hunk of copper tubes as a capacitor and find the charge density based on the voltage applied, Q=VC, C=20LIn(c/b) .)arrow_forwardWhy is the following situation impossible? Figure P28.46 shows an experimental technique for altering the direction of travel for a charged particle. A particle of charge q = 1.00 C and mass m = 2.00 1015 kg enters the bottom of the region of uniform magnetic field at speed = 2.00 105 m/s, with a velocity vector perpendicular to the field lines. The magnetic force on the particle causes its direction of travel to change so that it leaves the region of the magnetic field at the top traveling at an angle from its original direction. The magnetic field has magnitude B = 0.400 T and is directed out of the page. The length h of the magnetic field region is 0.110 m. An experimenter performs the technique and measures the angle at which the particles exit the top of the field. She finds that the angles of deviation are exactly as predicted. Figure P28.46arrow_forwardWithin the green dashed circle show in Figure P30.21, the magnetic field changes with time according to the expression B = 2.00t3 4.00t2 + 0.800, where B is in teslas, t is in seconds, and R = 2.50 cm. When t = 2.00 s, calculate (a) the magnitude and (b) the direction of the force exerted on an electron located at point P, which is at a distance r = 5.00 cm from the center of the circular field region. (c) At what instant is this force equal to zero? Figure P30.21arrow_forward
arrow_back_ios
arrow_forward_ios
Recommended textbooks for you
- Principles of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningPhysics for Scientists and EngineersPhysicsISBN:9781337553278Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningPhysics for Scientists and Engineers with Modern ...PhysicsISBN:9781337553292Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning
- Physics for Scientists and Engineers: Foundations...PhysicsISBN:9781133939146Author:Katz, Debora M.Publisher:Cengage Learning
Principles of Physics: A Calculus-Based Text
Physics
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
Physics for Scientists and Engineers
Physics
ISBN:9781337553278
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
Physics for Scientists and Engineers with Modern ...
Physics
ISBN:9781337553292
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
Physics for Scientists and Engineers: Foundations...
Physics
ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Cengage Learning