Chapter 3.4, Problem 21PTS

Interpretation Introduction

Interpretation: More acidic proton to be identified in following compound.

Concept Introduction

Hybridization: The acidity also predicts by hybridization in which the negative charge present on ${\text{sp, sp}}^{\text{2}}$ and ${\text{sp}}^{\text{3}}$ hybridized orbital. Orbital is more stability means more acidic. Increasing order of stability of the orbital are,

                               ${\text{sp > sp}}^{\text{2 }}{\text{> sp}}^{\text{3}}.$

${\text{PK}}_{\text{a}}$Value: The ${\text{pK}}_{\text{a}}$ value computes the acidity of an acid. This value depends upon the chemical property and identity of the compound.

${\text{pK}}_{\text{a}}$ ${\text{= - log K}}_{\text{a}}$

Where,

${\text{K}}_{\text{a}}$ is the measure of strength of an acid. If the acid is strong means ${\text{K}}_{\text{a}}$ on the order of ${\text{10}}^{\text{10}}$ and weak means ${\text{K}}_{\text{a}}$ on the order of ${\text{10}}^{-50}.$ Strong acid means ${\text{pK}}_{\text{a}}$ value is low value and Weak acid means ${\text{pK}}_{\text{a}}$ value is high.

If we know which proton is the more acidic and which proton is the less acidic we can make the determination regarding basicity.