Chapter 3.4, Problem 30E

To determine

To find: The $x$ coordinates of the position of the object at time $t=4$ .

Answer to Problem 30E

The value of the $x$ coordinate is $5$ .

Explanation of Solution

Given Data:

The given expression is,

  $x\left(t\right)=4t^2-16{\left(t\right)}^2+15t$

Calculation:

Consider that since the particle move along the line $y=2$ it is at the point $\left(5,2\right)$ for $x\left(t\right)$ and for $x\left(t\right)=5$ .

Then,

  $\begin{array}{c}x\left(t\right)=4t^2-16{\left(t\right)}^2+15t\\ =5\end{array}$

Consider the value of $t$ by the help of scientist calculator is,

  $t=2.83$