Physics for Scientists and Engineers with Modern Physics, Technology Update
Physics for Scientists and Engineers with Modern Physics, Technology Update
9th Edition
ISBN: 9781305401969
Author: SERWAY, Raymond A.; Jewett, John W.
Publisher: Cengage Learning
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Chapter 35, Problem 33P
To determine

The refractive index of the prism.

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A light ray traveling in air is incident on one face of a right-angle prism with index of refraction n = 1.49, as shown in Figure P22.54, and the ray follows the path shown in the figure. Assuming that θ = 58.0° and the base of the prism is mirrored, determine the angle made by the outgoing ray with the normal to the right face of the prism.?degrees
A laser beam is incident on a 45°–45°–90° prism perpendicularto one of its faces, as shown in Figure P22.20. The transmittedbeam that exits the hypotenuse of the prism makes anangle of Θ= 15.0° with the direction of the incident beam.Find the index of refraction of the prism.
A ray of light strikes a flat block of glass at an incidence angle of ?1 = 38.6°. The glass is 2.00 cm thick and has an index of refraction that equals ng = 1.52.   a.) The distance d separates the twice-bent ray from the path it would have taken without the glass in the way. What is this distance (in cm)?   b.) At what speed (in m/s) does the light travel within the glass?   c.) How many nanoseconds does the light take to pass through the glass along the angled path shown here?

Chapter 35 Solutions

Physics for Scientists and Engineers with Modern Physics, Technology Update

Ch. 35 - Prob. 6OQCh. 35 - Prob. 7OQCh. 35 - Prob. 8OQCh. 35 - Prob. 9OQCh. 35 - Prob. 10OQCh. 35 - Prob. 11OQCh. 35 - Prob. 12OQCh. 35 - Prob. 13OQCh. 35 - Prob. 14OQCh. 35 - Prob. 15OQCh. 35 - Prob. 1CQCh. 35 - Prob. 2CQCh. 35 - Prob. 3CQCh. 35 - Prob. 4CQCh. 35 - Prob. 5CQCh. 35 - Prob. 6CQCh. 35 - Prob. 7CQCh. 35 - Prob. 8CQCh. 35 - Prob. 9CQCh. 35 - Prob. 10CQCh. 35 - Prob. 11CQCh. 35 - (a) Under what conditions is a mirage formed?...Ch. 35 - Prob. 13CQCh. 35 - Prob. 14CQCh. 35 - Prob. 15CQCh. 35 - Prob. 16CQCh. 35 - Prob. 17CQCh. 35 - Prob. 1PCh. 35 - Prob. 2PCh. 35 - In an experiment to measure the speed of light...Ch. 35 - As a result of his observations, Ole Roemer...Ch. 35 - Prob. 5PCh. 35 - Prob. 6PCh. 35 - Prob. 7PCh. 35 - Prob. 8PCh. 35 - Prob. 9PCh. 35 - Prob. 10PCh. 35 - Prob. 11PCh. 35 - A ray of light strikes a flat block of glass (n =...Ch. 35 - Prob. 13PCh. 35 - Prob. 14PCh. 35 - Prob. 15PCh. 35 - Prob. 16PCh. 35 - Prob. 17PCh. 35 - Prob. 18PCh. 35 - When you look through a window, by what time...Ch. 35 - Two flat, rectangular mirrors, both perpendicular...Ch. 35 - Prob. 21PCh. 35 - Prob. 22PCh. 35 - Prob. 23PCh. 35 - Prob. 24PCh. 35 - Prob. 25PCh. 35 - Prob. 26PCh. 35 - Prob. 27PCh. 35 - Prob. 28PCh. 35 - Prob. 29PCh. 35 - Prob. 30PCh. 35 - Prob. 31PCh. 35 - Prob. 32PCh. 35 - Prob. 33PCh. 35 - A submarine is 300 m horizontally from the shore...Ch. 35 - Prob. 35PCh. 35 - Prob. 36PCh. 35 - Prob. 37PCh. 35 - Prob. 39PCh. 35 - Prob. 40PCh. 35 - Prob. 41PCh. 35 - Prob. 42PCh. 35 - Prob. 43PCh. 35 - Prob. 44PCh. 35 - Assume a transparent rod of diameter d = 2.00 m...Ch. 35 - Consider a light ray traveling between air and a...Ch. 35 - Prob. 47PCh. 35 - Prob. 48PCh. 35 - Prob. 49PCh. 35 - Prob. 50PCh. 35 - Prob. 51APCh. 35 - Prob. 52APCh. 35 - Prob. 53APCh. 35 - Prob. 54APCh. 35 - Prob. 55APCh. 35 - Prob. 56APCh. 35 - Prob. 57APCh. 35 - Prob. 58APCh. 35 - Prob. 59APCh. 35 - A light ray enters the atmosphere of a planet and...Ch. 35 - Prob. 61APCh. 35 - Prob. 62APCh. 35 - Prob. 63APCh. 35 - Prob. 64APCh. 35 - Prob. 65APCh. 35 - Prob. 66APCh. 35 - Prob. 67APCh. 35 - Prob. 68APCh. 35 - Prob. 69APCh. 35 - Prob. 70APCh. 35 - Prob. 71APCh. 35 - Prob. 72APCh. 35 - Prob. 73APCh. 35 - Prob. 74APCh. 35 - Prob. 75APCh. 35 - Prob. 76APCh. 35 - Prob. 77APCh. 35 - Prob. 78APCh. 35 - Prob. 79APCh. 35 - Prob. 80APCh. 35 - Prob. 81CPCh. 35 - Prob. 82CPCh. 35 - Prob. 83CPCh. 35 - Prob. 84CPCh. 35 - Prob. 85CPCh. 35 - Prob. 86CPCh. 35 - Prob. 87CP
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Laws of Refraction of Light | Don't Memorise; Author: Don't Memorise;https://www.youtube.com/watch?v=4l2thi5_84o;License: Standard YouTube License, CC-BY