Concept explainers
(a)
The maximum angle of incidence for which the phenomena of total internal reflection occurs at the left vertical surface.
(a)
Answer to Problem 35.68AP
Explanation of Solution
Given Info: The light of wavelength
The refractive index of the polystyrene is
Figure (I)
For total internal reflection from the left vertical surface the angle of incidence for the vertical surface must be greater than the critical angle.
The formula to calculate the critical angle is,
Here,
Substitute
From equation (1) the value of the angle
From Figure (1) in triangle
Substitute
Thus the value of
Formula to calculate the value of
Here,
Substitute
As the angle
Thus any value of
Conclusion:
Therefore, total internal reflection will occur at the left vertical surface for any angle less than
(b)
The angle of incidence if the polystyrene slab is immersed in water.
(b)
Answer to Problem 35.68AP
Explanation of Solution
Explanation
Given info: The refractive index of water is
For the polystyrene slab surrounded in water the value of critical angle is,
Substitute
The value of
From figure (1) in triangle
Substitute
From Snell’s Law, calculate the value of the angle of incidence.
Here,
Substitute
Thus when the polystyrene slab is immersed in water the angle of incidence is
Conclusion:
Therefore, the total internal reflection will occur for angle of incidence
(c)
The angle of incidence for the phenomena of total internal reflection if the polystyrene slab is immersed in carbon disulphide.
(c)
Answer to Problem 35.68AP
Explanation of Solution
Explanation
Given info: The refractive index of carbon disulphide is
The phenomena of total internal reflection only takes place when the light ray is travelling form a higher refractive index material to a low refractive index material.
For the case where the polystyrene slab is immersed in the carbon disulphide the light ray at the interface of the left vertical wall will not undergo the total internal reflection as at the interface the light will be propagating form a lower refractive index material to a higher refractive material and for the phenomena of total internal reflection to occur the light must be travelling form higher refractive index material to a low refractive index material.
Hence, the phenomena of total internal reflection will not take place when the slab is immersed in carbon disulphide.
Conclusion:
Therefore, the phenomena of total internal reflection will not take place when the slab is immersed in carbon disulphide.
Want to see more full solutions like this?
Chapter 35 Solutions
PHYSICS F/...V.1 (LL)-W/ACCESS >CUSTOM<
- How many times will the incident beam in Figure P34.33 (page 922) be reflected by each of the parallel mirrors? Figure P34.33arrow_forwardFigure P23.28 shows a curved surface separating a material with index of refraction n1 from a material with index n2. The surface forms an image I of object O. The ray shown in red passes through the surface along a radial line. Its angles of incidence and refraction are both zero, so its direction does not change at the surface. For the ray shown in blue, the direction changes according to n1 sin 1 = n2 sin 2. For paraxial rays, we assume 1 and 2 are small, so we may write n1 tan 1 n2 tan 2. The magnification is defined as M = h/h. Prove that the magnification is given by M = n1q/n2p. Figure P23.28arrow_forwardCurved glassair interfaces like those observed in an empty shot glass make it possible for total internal reflection to occur at the shot glasss internal surface. Consider a glass cylinder (n = 1.54) with an outer radius of 2.50 cm and an inner radius of 2.00 cm as shown in Figure P38.105. Find the minimum angle i such that there is total internal reflection at the inner surface of the shot glass. FIGURE P38.105 Problems 105 and 106.arrow_forward
- An object is placed a distance of 10.0 cm to the left of a thin converging lens of focal length f = 8.00 cm, and a concave spherical mirror with radius of curvature +18.0 cm is placed a distance of 45.0 cm to the right of the lens (Fig. P38.129). a. What is the location of the final image formed by the lensmirror combination as seen by an observer positioned to the left of the object? b. What is the magnification of the final image as seen by an observer positioned to the left of the object? c. Is the final image formed by the lensmirror combination upright or inverted? FIGURE P38.129arrow_forwardA man inside a spherical diving bell watches a fish through a window in the bell, as in Figure P23.26. If the diving bell has radius R = 1.75 m and the fish is a distance p = 1 00 m from the window, calculate (a) the image distance and (b) the magnification. Neglect the thickness of the window. Figure P23.26arrow_forward
- Physics for Scientists and Engineers with Modern ...PhysicsISBN:9781337553292Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningPhysics for Scientists and EngineersPhysicsISBN:9781337553278Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningPrinciples of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning
- Physics for Scientists and Engineers: Foundations...PhysicsISBN:9781133939146Author:Katz, Debora M.Publisher:Cengage LearningCollege PhysicsPhysicsISBN:9781305952300Author:Raymond A. Serway, Chris VuillePublisher:Cengage LearningCollege PhysicsPhysicsISBN:9781285737027Author:Raymond A. Serway, Chris VuillePublisher:Cengage Learning