BIG IDEAS MATH Algebra 1: Common Core Student Edition 2015

1st Edition

ISBN: 9781608408382

Author: HOUGHTON MIFFLIN HARCOURT

Publisher: Houghton Mifflin Harcourt

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Expert Solution & Answer

Chapter 3.5, Problem 50E

Solution

a.

To describe:The commutation to school in words.

First 10 minutes commute is by walking, then 4 minutes rest, then commute by bus with speed for 4 minutes.

Given:

The commute to school by walking and riding by bus is shown by distance- time graph below:

Formula/ concept used:

The slope of distance time graph gives the velocity of the object. The slope of a line is the ratio y- distance to x -distance.

Description:

The commute is described by the graph initial point O→A→B→C (final point).

Motion O to A:The slope of graph is very small so commute from O to A is by walking for first 10 minutes of the journey.

Motion A to B:The slope of the graph O to B is zero so the speed is also zero. Thus from A to B for 10^t^h to 14^t^h minutes I take rest.

Motion B to C:For the motion from 14^t^h to 18^t^h minutes, the slope of the graph is higher so commute from B to C is by bus for first4 minutes of the journey.

Conclusion:

First 10 minutes commute is by walking, then 4 minutes rest, then commute by bus with speed for 4 minutes.

b.

To calculate:The slope of different parts of the graph in Part (a) and interpret it.

First 10 minutes commute is with speed 3 miles/ hour, then 4 minutes rest then commute by bus with speed 45 miles / hour for 4 minutes.

Given:

The distance −time graph in part (a)

Concept used:

The slope of distance −time graph gives the velocity/ speed of the object.

Calculations:

Motion O to A: My speed from O to A is approximately v=aAOa=0.5 mile10 minutes=0.05 miles/min. or v=0.05×60=3 miles/hour . Thus, commute from O to A is by walking for first 10 minutes of the journey.

Motion A to B: The slope of the graph O to B is zero so the speed is also zero. Thus from A to B for 10^t^h to 14^t^h minutes I take rest.

Motion B to C:For the motion from 14^t^h to 18^t^h minutes, the speed is v=cCcb=3 miles4 minutes=0.75 miles/min. or v=0.75×60=45miles/hour . Thus, commute from B to C is by bus for first4 minutes of the journey.

Conclusion:

First 10 minutes commute is with speed 3 miles/ hour, then 4 minutes rest then commute by bus with speed 45 miles / hour for 4 minutes.

Chapter 3.5, Problem 49E

Chapter 3.5, Problem 51E

Chapter 3 Solutions

BIG IDEAS MATH Algebra 1: Common Core Student Edition 2015

Ch. 3.1 - Prob. 1E Ch. 3.1 - Prob. 2E Ch. 3.1 - Prob. 3E Ch. 3.1 - Prob. 4E Ch. 3.1 - Prob. 5E Ch. 3.1 - Prob. 6E Ch. 3.1 - Prob. 7E Ch. 3.1 - Prob. 8E Ch. 3.1 - Prob. 9E Ch. 3.1 - Prob. 10E

Ch. 3.1 - Prob. 11E Ch. 3.1 - Prob. 12E Ch. 3.1 - Prob. 13E Ch. 3.1 - Prob. 14E Ch. 3.1 - Prob. 15E Ch. 3.1 - Prob. 16E Ch. 3.1 - Prob. 17E Ch. 3.1 - Prob. 18E Ch. 3.1 - Prob. 19E Ch. 3.1 - Prob. 20E Ch. 3.1 - Prob. 21E Ch. 3.1 - Prob. 22E Ch. 3.1 - Prob. 23E Ch. 3.1 - Prob. 24E Ch. 3.1 - Prob. 25E Ch. 3.1 - Prob. 26E Ch. 3.1 - Prob. 27E Ch. 3.1 - Prob. 28E Ch. 3.1 - Prob. 29E Ch. 3.1 - Prob. 30E Ch. 3.1 - Prob. 31E Ch. 3.1 - Prob. 32E Ch. 3.1 - Prob. 33E Ch. 3.1 - Prob. 34E Ch. 3.1 - Prob. 35E Ch. 3.1 - Prob. 36E Ch. 3.1 - Prob. 37E Ch. 3.1 - Prob. 38E Ch. 3.1 - Prob. 39E Ch. 3.1 - Prob. 40E Ch. 3.1 - Prob. 41E Ch. 3.1 - Prob. 42E Ch. 3.1 - Prob. 43E Ch. 3.1 - Prob. 44E Ch. 3.1 - Prob. 45E Ch. 3.1 - Prob. 46E Ch. 3.1 - Prob. 47E Ch. 3.1 - Prob. 48E Ch. 3.1 - Prob. 49E Ch. 3.1 - Prob. 50E Ch. 3.1 - Prob. 51E Ch. 3.2 - Prob. 1E Ch. 3.2 - Prob. 2E Ch. 3.2 - Prob. 3E Ch. 3.2 - Prob. 4E Ch. 3.2 - Prob. 5E Ch. 3.2 - Prob. 6E Ch. 3.2 - Prob. 7E Ch. 3.2 - Prob. 8E Ch. 3.2 - Prob. 9E Ch. 3.2 - 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Prob. 5CA Ch. 3 - Prob. 6CA Ch. 3 - Prob. 7CA Ch. 3 - Prob. 8CA Ch. 3 - Prob. 9CA Ch. 3 - Prob. 10CA

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