Concept explainers
The shortest distance from the central maximum for which the bright fringes for the two wavelengths coincide.
Answer to Problem 82PQ
The shortest distance from the central maximum for which the bright fringes for the two wavelengths coincide is
Explanation of Solution
Write the for the phase difference for the wave of light
Here,
Write the for the phase difference for the wave of light
Here,
Divide equation (I) by (II) to get the value of
Write the expression for the angle made by a particular interference fringe from the central maximum of the screen.
Here,
Conclusion:
Substitute
On comparison of values of equation (V),
Substitute
Substitute
Therefore, the shortest distance from the central maximum for which the bright fringes for the two wavelengths coincide is
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Chapter 35 Solutions
Physics for Scientist and Engineers (Foundations And Connection; Volume I and II) LLF edition
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