Concept explainers
(a)
The image of the fish located
(a)
Answer to Problem 36P
The image of the fish located
Explanation of Solution
Write the relation between the refractive indices, object distance, image distance and the radius of curvature.
Here,
Conclusion:
Substitute
Substitute
Therefore, the image of the fish located
(b)
The magnification of the image of the fish located
(b)
Answer to Problem 36P
The magnification of the image of the fish located
Explanation of Solution
Write the expression for the magnification of the image of the fish.
Conclusion:
Substitute
Substitute
Therefore, the magnification of the image of the fish located
(c)
The reason that we don’t need to know the refractive index of plastic in the problem.
(c)
Answer to Problem 36P
The reason that we don’t need to know the refractive index of plastic in the problem is that the plastic will not change the direction of the ray passing through it.
Explanation of Solution
The uniform thickness of the plastic will make sure that the entry and exit rays to be nearly parallel. There will be a slight displacement only but no change in the direction of the ray passing through the plastic.
Therefore, the reason that we don’t need to know the refractive index of plastic in the problem is that the plastic will not change the direction of the ray passing through it.
(d)
Whether the image of the fish is farther from the front surface than the fish itself if this aquarium were very long from front to back.
(d)
Answer to Problem 36P
Yes, the image of the fish will be farther from the front surface than the fish itself if this aquarium were very long from front to back.
Explanation of Solution
The image of the fish will be farther from the front surface than the fish itself if this aquarium were very long from front to back.
Therefore, the image of the fish will be farther from the front surface than the fish itself if this aquarium were very long from front to back.
(e)
The magnification.
(e)
Answer to Problem 36P
The magnification is
Explanation of Solution
Assume that the image distance is
Conclusion:
Substitute
Therefore, the magnification is
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Chapter 36 Solutions
Physics For Scientists And Engineers With Modern Physics, 9th Edition, The Ohio State University
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