Concept explainers
Slit 1 of a double-slit is wider than slit 2 so that the light from slit 1 has an amplitude exactly 3 times that of the light from slit 2. Show that Equation 36.9 is replaced by the following equation for this situation:
Begin by assuming that the total magnitude of the electric field at point P on the screen in Figure 36.4 is the superposition of two waves, with electric field magnitudes
The phase angle ϕ in E2 is due to the extra path length traveled by the lower beam in Figure 36.4. You will need to evaluate the integral of the square of the sine function over one period. Refer to Figure 32.5 for an easy way to perform this evaluation. You might find the following trigonometric identities helpful:
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Chapter 36 Solutions
Bundle: Physics for Scientists and Engineers with Modern Physics, Loose-leaf Version, 10th + WebAssign Printed Access Card for Serway/Jewett's Physics for Scientists and Engineers, 10th, Multi-Term
- In a double-slit interference experiment, d is the distance between the centers of the slits and w is the width of each slit, as shown in the figure above. For incident plane waves, if an interference maximum on a distant screen will fall at a diffractive minimum, which of the following relations between d and w is correct? @ 3d=2w @ 2d=3w. @d=3¹/2w. @d=2¹/2w @ 2d=w.arrow_forwardThe spacing between principal planes in a NaCl crystal is 2.82x10^-10 m. It is found that a first order Bragg reflection of a monochromatic X-ray beam occurs at an angle of 10°. From this information we can say that the wavelength λ of the X-rays and the angle θ2 corresponding to the second-order spectrum are:Choose an answer between the letters A and D from the image below and justify your answerarrow_forwardConsider a variety of colors of visible light (say 400 nm to 700 nm) falling onto a pair of slits. a) What is the smallest separation (in nanometers) between two slits that will produce a second-order maximum for some visible light? b) What is the smallest separation (in nanometers) between two slits that will produce a second-order maximum for all visible light?arrow_forward
- Figure 1 shows the viewing screen in a double-slit experiment with monochromatic light. Fringe C is the central maximum. The fringe separation is Δy Suppose the wavelength of the light is 430 nm . How much farther is it from the dot on the screen in the center of fringe E to the left slit than it is from the dot to the right slit?arrow_forwardI already know the answer to this practice problem, and it is shown is the image. I do not know how to get to the answer though, so seeing the steps and equations would be much appreciated.arrow_forwardFor this problem, I know the answer is B but I do not know how to get there. Seeing the steps and equations would be much appreciated. Thank youarrow_forward
- The light intensity vs. position graph of a double-slit experiment is shown below. The graph was made with helium-neon laser light of wavelength 630 nm shined through two very narrow slits separated by a small distance. The slits were 2.0 meters away from the probe. What is the path-length difference (from the two slits to the screen) when the probe is at position 9.0 mm, in nm? Your answer needs to have 2 significant figures, including the negative sign in your answer if needed. Do not include the positive sign if the answer is positive. No unit is needed in your answer, it is already given in the question statement. Lasilian Position of probe (mm) Light levelarrow_forwardIn a Young's double-slit experiment, a set of parallel slits with a separation of 0.130 mm is illuminated by light having a wavelength of 550 nm and the interference pattern observed on a screen 3.50 m from the slits. (a) What is the difference in path lengths from the two slits to the location of a fifth order bright fringe on the screen? 1.1 Your response differs from the correct answer by more than 10%. Double check your calculations. um (b) What is the difference in path lengths from the two slits to the location of the fifth dark fringe on the screen, away from the center of the pattern? X umarrow_forwardThe ship in the figure below travels along a straight line parallel to the shore and a distance d = 710 m from it. The ship's radio receives simultaneous signals of the same frequency from antennas A and B, separated by a distance L = 750 m. The signals interfere constructively at point C, which is equidistant from A and B. The signal goes through the first minimum at point D, which is directly outward from the shore from point B. Determine the wavelength of the radio waves.arrow_forward
- Please help me with this question.arrow_forwardX rays of wavelength 0.0820 nm are scattered from the atoms of a crystal. The second-order maximum in the Bragg reflection occurs when the angle is 20.5°. (Figure 1) For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of X-ray diffraction. Part A What is the spacing between adjacent atomic planes in the crystal? Express your answer in nanometers. ΓΙ ΑΣΦ d = Submit Previous Answers Request Answer ? nmarrow_forwardQ. A grating having 5000 lines per cm is used under normal incidence of light. What will happen to the observed spectrum if 90% of the ruled width of the grating is covered? Please solve this, urgently. Thankyou!!!arrow_forward
- University Physics Volume 3PhysicsISBN:9781938168185Author:William Moebs, Jeff SannyPublisher:OpenStaxPrinciples of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningPhysics for Scientists and Engineers: Foundations...PhysicsISBN:9781133939146Author:Katz, Debora M.Publisher:Cengage Learning