Explanation Given Info: The energy of the metastable state of helium is E 1 = 20.61 eV , the excited energy of the neon atoms is E 2 = 20.66 eV and the wavelength of the photon emitted in the lasing transition is 632.8 nm . The efficiency of the lasing action of the laser is the ratio of the energy of a single photon to the energy required to reach the highest state in the production cycle for that photon. The highest energy reached in the cycle is E 2 = 20.66 eV . Write the equation for the efficiency of the laser. ε = E γ E 2 (1) Here, ε is the efficiency of the laser E γ is the energy of the photon Write the equation for E γ . E γ = h c λ Here, λ is the wavelength of the photon h is the Planck’s constant c is the speed of light in vacuum The value of h is 4.1357 × 10 − 15 eV ⋅ s and the value of c is 3.00 × 10 8 m/s . Substitute 4.1357 × 10 − 15 eV ⋅ s for h , 3.00 × 10 8 m/s for c and 632.8 nm for λ in the above equation to find E γ

Essential University Physics (3rd Edition)

3rd Edition

ISBN: 9780134202709

Author: Richard Wolfson

Publisher: PEARSON

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Chapter 36, Problem 74P

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The maximum possible efficiency of the laser.

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Chapter 36, Problem 73P

Chapter 36, Problem 75P

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Chapter 36 Solutions

Essential University Physics (3rd Edition)

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