Explanation Given Info: The energy of the K α line of Molybdenum is 17.4 keV . Write the equation for the wavelength of the x-ray. λ = h c E Here, λ is the wavelength of the x-ray h is the Planck’s constant c is the speed of light in vacuum E is the energy of the x-ray The value of h is 4.1357 × 10 − 15 eV ⋅ s and the value of c is 3.00 × 10 8 m/s . Substitute 4.1357 × 10 − 15 eV ⋅ s for h , 3.00 × 10 8 m/s for c and 17 .4 keV for E in the above equation to find λ . λ = ( 4.1357 × 10 − 15 eV ⋅ s ) ( 3.00 × 10 8 m/s ) ( 17

Essential University Physics (3rd Edition)

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ISBN: 9780134202709

Author: Richard Wolfson

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Chapter 36, Problem 76PP

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The closest value of the wavelength of the Kα line of Molybdenum.

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Chapter 36, Problem 75P

Chapter 36, Problem 77PP

Chapter 36 Solutions

Essential University Physics (3rd Edition)

Ch. 36.1 - Prob. 36.1GI Ch. 36.2 - Prob. 36.2GI Ch. 36.3 - Prob. 36.3GI Ch. 36.4 - Prob. 36.4GI Ch. 36.5 - Prob. 36.5GI Ch. 36 - Prob. 1FTD Ch. 36 - Prob. 2FTD Ch. 36 - Prob. 3FTD Ch. 36 - Prob. 4FTD Ch. 36 - Prob. 5FTD

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