(a)
The potential energy of attraction of the ions.
(a)
Answer to Problem 21P
Thepotential energy of attraction of the ions is
Explanation of Solution
Given:
The equilibrium separation of the
Formula used:
The expression for potential energy of attraction is given by,
Calculation:
The potential energy of attraction is calculated as,
Conclusion:
Therefore, the potential energy of attraction of the ions is
(b)
The value of dissociation energy.
(b)
Answer to Problem 21P
The value of dissociation energy is
Explanation of Solution
Given:
The ionization energy of potassium is
The
Formula used:
The expression for total potential energy of the molecule neglecting energy of repulsion is given by,
The expression for dissociation energy is given by,
Here,
Calculation:
Difference between the ionization energy of potassium and the electron affinity of fluorine
The dissociation energy is calculated as,
Conclusion:
Therefore, the value of dissociation energy is
(c)
The energy due to repulsion of the ions at the equilibrium separation.
(c)
Answer to Problem 21P
The energy due to repulsion of the ions at the equilibrium separation is
Explanation of Solution
Given:
The measured dissociation energy
Formula used:
The expression for energy due to repulsion of the ions at equilibrium separation is given by,
Calculation:
The energy due to repulsion of the ions at equilibrium separation is calculated as,
Conclusion:
Therefore, the energy due to repulsion of the ions at the equilibrium separation is
Want to see more full solutions like this?
Chapter 37 Solutions
Physics for Scientists and Engineers, Vol. 3
- Assume that the total volume of a metal sample is the sumof the volume occupied by the metal ions making up the lattice andthe (separate) volume occupied by the conduction electrons. Thedensity and molar mass of sodium (a metal) are 971 kg/m3 and 23.0g/mol, respectively; assume the radius of the Na+ ion is 98.0 pm. (a)What percent of the volume of a sample of metallic sodium is occupiedby its conduction electrons? (b) Carry out the same calculationfor copper, which has density, molar mass, and ionic radius of8960 kg/m3, 63.5 g/mol, and 135 pm, respectively. (c) For which ofthese metals do you think the conduction electrons behave morelike a free-electron gas?arrow_forwardCompute the magnitude of the electrostatic attraction energy between a silver cation (radius 129 pm) and a sulfide anion (radius 170 pm). Give your answer in al. Note that magnitude means "absolute value" i.e. answer without arithmetic +/- sign.arrow_forwardConsider the original Stern–Gerlach experiment employing an atomic beam of silver, for which the magnetic moment is due entirely to the spin of the single valence electron of the silver atom. Assuming the magnetic field B has magnitude 0.500 T, compute the energy difference in electron volts of the silver atoms in the two exiting beams.arrow_forward
- Calculate the number of Frenkel defects per cubic meter in potassium chlorideat 500degC. The energy required to form each Frenkeldefect is 2.6 eV, whereasthe density for KCl is 1.955 g/cm3.arrow_forwardCalculate the net energy of a NaCl ion paired separated by an inter-ionic distance of 1.475 nm, If the net force between the ion pair is 6.725 x 10^-12 N. n=9 z1= +1 z2= -1arrow_forwardin a p type germanium ni=2.1×10^19m^-3 denisty of baran 4.5^23 atoms/m^3 the electron nd holes mobility are. 4 nd. 2m^2v^-2s^-1 resp. what is its conductivity befor nd after additiin of boran atomsarrow_forward
- At a certain temperature, the electron and hole mobilities in intrinsic germanium are given as 0.43 and 0.21 m2/V s, respectively. If the electron and hole concentrations are both 2.3 x 10'® m, find the conductivity at this temperature.arrow_forwardWhat is the probability that, at a temperature of T = 300 K, an electron will jump across the energy gap Eg (= 5.5 eV) in a diamond that has a mass equal to the mass of Earth? Use the molar mass of carbon in Appendix F; assume that in diamond there is one valence electron per carbon atom.arrow_forwardThe atomic radii of a divalent cation and a monovalent anion are 0.074 nm and 0.128 nm, respectively. Calculate the force of attraction between these two ions at their equilibrium interionic separation (i.e., when the ions just touch one another) and the force of repulsion at the same distance.arrow_forward
- Approximate the donor binding energy (theamount of energy required for a donor atom such as Sn to release an electron into the conductionband) for a) GaAs and b) InP.arrow_forwardWhen a photon enters the depletion zone of a p-n junction, the photon can scatter from the valence electrons there, transferring part of its energy to each electron, which then jumps to the conduction band. Thus, the photon creates electron–hole pairs. For this reason, the junctions are often used as light detectors, especially in the x-ray and gamma-ray regions of the electromagnetic spectrum. Suppose a single 662 keV gamma-ray photon transfers its energy to electrons in multiple scattering events inside a semiconductor with an energy gap of 1.1 eV, until all the energy is transferred. Assuming that each electron jumps the gap from the top of the valence band to the bottom of the conduction band, find the number of electron – hole pairs created by the process.arrow_forwardSn, C, and Si, Ge are all group XIV elements. Yet, Sn is a conductor, C is an insulator while Si and Ge are semiconductors. Why?arrow_forward
- Modern PhysicsPhysicsISBN:9781111794378Author:Raymond A. Serway, Clement J. Moses, Curt A. MoyerPublisher:Cengage LearningPhysics for Scientists and Engineers with Modern ...PhysicsISBN:9781337553292Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningUniversity Physics Volume 3PhysicsISBN:9781938168185Author:William Moebs, Jeff SannyPublisher:OpenStax
- Glencoe Physics: Principles and Problems, Student...PhysicsISBN:9780078807213Author:Paul W. ZitzewitzPublisher:Glencoe/McGraw-Hill