Concept explainers
Four trials of Young's double-slit experiment are
(i)
Ranking of the trials from largest to the smallest angular distance.
Answer to Problem 37.2OQ
The Ranking of the trials from largest to the smallest angular distance is
Explanation of Solution
Given info: For case (a) and case (b) the slit separation is
Write the expression for constructive interference for the bright fringes.
Here,
The value of
Substitute
Case (a);
The wavelength of the blue light is
Substitute
Thus, the value of angular distance is
Case (b);
The wavelength of the red light is
Substitute
Thus, the value of angular distance is
Case (c);
The wavelength of the red light is
Substitute
Thus, the value of angular distance is
Case (d);
The wavelength of the red light is
Substitute
Thus, the value of angular distance is
The ranking of the angular distances of all the cases is,
Conclusion:
Therefore, the ranking of the trials from largest to the smallest angular distance is
(ii)
Ranking of the trials on the basis of their distance between the central maximum and the first order side maximum on the screen.
Answer to Problem 37.2OQ
The Ranking of the trials on the basis of their distance between the central maximum and the first order side maximum on the screen is
Explanation of Solution
Given info: For case (a) and case (b) the slit separation is
Write the expression for distance between the central maximum and the screen.
Here,
Case (a);
The wavelength of the blue light is
Substitute
Thus, the value of
Case (b);
The wavelength of the red light is
Substitute
Thus, the value of
Case (c);
The wavelength of the red light is
Substitute
Thus, the value of
Case (d);
The wavelength of the red light is
Substitute
Thus, the value of
The ranking of the distance between the central maximum and the screen of all the cases is,
Conclusion:
Therefore, the ranking of the trials on the basis of their distance between the central maximum and the first order side maximum on the screen is
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Chapter 37 Solutions
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