(a)
The location of the image.
(a)
Answer to Problem 55PQ
The location of the image is
Explanation of Solution
In case of convex mirror, no matter where the object is placed. The image is always erect and virtual.
Write the expression for focal length.
Here,
Write the expression for mirror equation.
Here,
Solve the above equation for
Simplify the above equation.
Conclusion:
Substitute
Substitute,
Therefore, the location of the image is
(b)
The magnification of the image.
(b)
Answer to Problem 55PQ
The magnification of the image is
Explanation of Solution
Write the expression for magnification in case of mirror.
Conclusion:
Substitute,
Therefore, the magnification of the image is
(c)
The image is inverted or upright.
(c)
Answer to Problem 55PQ
The image is upright.
Explanation of Solution
The image is upright because the magnification value is positive as calculated in the part (b). And as the image distance is negative as calculated in part (a), it implies the image is virtual.
Hence, the image is virtual and upright.
Therefore, the image is upright.
(d)
The height of the image.
(d)
Answer to Problem 55PQ
The height of the image is
Explanation of Solution
Write the expression for magnification in case of mirror.
Here,
Solve the above equation for
Conclusion:
Substitute
Therefore, the height of the image is
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Chapter 37 Solutions
Physics for Scientists and Engineers: Foundations and Connections, Advance Edition, Volume 2
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