Concept explainers
To show that the equation
Answer to Problem 74CP
It is shown that the equation
Explanation of Solution
Write the expression to find the magnitude of the light arriving at some point
Rewrite the above equation as ratio with maximum amplitude.
Write the square of the expression.
Take the time average of the above equation.
Conclusion:
Write the expression for intensity.
Write the expression for maximum intensity.
Write the expression for the ratio of intensity to maximum intensity.
Rewrite the above equation to find the expression for intensity.
Therefore, it is shown that the equation
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Chapter 37 Solutions
Physics For Scientists And Engineers With Modern Physics, 9th Edition, The Ohio State University
- Table P35.80 presents data gathered by students performing a double-slit experiment. The distance between the slits is 0.0700 mm, and the distance to the screen is 2.50 m. The intensity of the central maximum is 6.50 106 W/m2. What is the intensity at y = 0.500 cm? TABLE P35.80arrow_forwardA Fraunhofer diffraction pattern is produced on a screen located 1.00 m from a single slit. If a light source of wavelength 5.00 107 m is used and the distance from the center of the central bright fringe to the first dark fringe is 5.00 103 m, what is the slit width? (a) 0.010 0 mm (b) 0.100 mm (c) 0.200 mm (d) 1.00 mm (e) 0.005 00 mmarrow_forwardCoherent light rays of wavelength strike a pair of slits separated by distance d at an angle 1, with respect to the normal to the plane containing the slits as shown in Figure P27.14. The rays leaving the slits make an angle 2 with respect to the normal, and an interference maximum is formed by those rays on a screen that is a great distance from the slits. Show that the angle 2 is given by 2=sin1(sin1md) where m is an integer.arrow_forward
- In Figure P27.7 (not to scale), let L = 1.20 m and d = 0.120 mm and assume the slit system is illuminated with monochromatic 500-nm light. Calculate the phase difference between the two wave fronts arriving at P when (a) = 0.500 and (b) y = 5.00 mm. (c) What is the value of for which the phase difference is 0.333 rad? (d) What is the value of for which the path difference is /4?arrow_forwardIn a Young’s double-slit experiment, light of wavelength 500 nm illuminates two slits that are separated by 1 mm. What is the separation distance between the central maximum (m = 0) and the 3rd order maximum (m = 3) on a screen 5.0 m from the slits? A. 0.10 cm. B. 0.25 cm. C. 0.50 cm. D. 0.75 cm. E 1.0 cm.arrow_forwardIn a double slit experiment, if the separation between the two slits is 0.050 mm and the distance from the slits to a screen is 2.5 m, find the spacing between the first-order and second-order bright fringes when coherent light of wavelength 600 nm illuminates the slits. A) 1.5 cm B) 3.0 cm C) 4.5 cm D) 6.0 cm E) 9.0 cmarrow_forward
- Two vertical slits of width 2.13 μm are separated by 24.4 μm and are illuminated by a laser with wavelength 514 nm. If a screen is placed at a distance of 1.96 m and we look at a location 23.8 cm horizontally from the center of the screen, what is the percentage of the single-slit intensity that we will see? [Include single-slit diffraction for this problem]arrow_forwardLight of wavelength 520 nm illuminates a slit of width 0.45 mm. (a) At what distance from the slit should a screen be placed if the first minimum in the diffraction pattern is to be 0.52 mm from the central maximum? 0.45 m 0.53 m 0.63 m 0.72 m (b) Calculate the width of the central maximum. 1.04 mm 2.08 mm 3.12 mm 4.16 mmarrow_forwardIn a two-slit experiment, the slit separation is 3.00*10-5 m. The interference pattern is recorded on a flat screen-like detector that is 2.00 m away from the slits. If the seventh bright fringe on the detector is 10.0 cm away from the central fringe, what is the wavelength of the light passing through the slits? A) 100 nm B) 204 nm C) 214 nm D) 224 nm E) 234 nmarrow_forward
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