(a) Explanation Write the expression to calculate the energy of the photon with wavelength λ . E = h c λ Here, E is the energy, h is the Planck’s constant, c is the velocity of light and λ is the wavelength. Conclusion: Substitute 6.626 × 10 − 34 kg ⋅ m 2 / s for h , 3 × 10 8 m / s for c in the above expression to find E . E = ( 6.626 × 10 − 34 kg ⋅ m 2 / s ) ( 3 × 10 8 m / s ) λ = ( 1 (b) To determine The energy of a 650 nm photon.

Physics for Scientists & Engineers with Modern Physics [With Access Code]

4th Edition

ISBN: 9780321712592

Author: GIANCOLI

Publisher: Pearson College Div

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Question

Chapter 37, Problem 96GP

(a)

To determine

The proof that the energy of the photon is given by E=1240 eV⋅nmλ(nm).

(b)

To determine

The energy of a 650 nm photon.

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Chapter 37, Problem 95GP

Chapter 37, Problem 97GP

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Chapter 37 Solutions

Physics for Scientists & Engineers with Modern Physics [With Access Code]

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The proof that the energy of the photon is given by E = 1240 eV ⋅ nm λ ( nm ) .

Solution Summary: The author explains the proof that the energy of the photon is given by E=hclambda.

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The proof that the energy of the photon is given by E=1240 eV⋅nmλ(nm).

The energy of a 650 nm photon.

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Chapter 37 Solutions