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Chapter 38, Problem 21P
To determine

The proof that uncertainty principle holds for a “wave packet” formed by two similar waves; width of each wave packet is Δx=2πΔk and ΔxΔp=h.

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(b) (deBroglie wave length) Determine the deBroglie wavelength (formula: p=h/2) of a grain of dust with diameter 1um, density 1kg m-3 and speed 1cm s. Compare your result with the diameter of the dust grain and the diameter of an atom. Comment?
(10) i) Use the quantum mechanical kinetic energy operator T, = to find the kinetic energy of the first 2m dx? excited state of the Particle in a Box (with n = 2). ii) Then, use the relationship of kinetic energy and momentum (KE = p?/2m) to find an equation for the de Broglie wavelength of the particle in a one-dimensional box as a function only of the box length L and quantum number n. iii) Sketch the wavefunction in the box to verify that the expression you obtained in part ii) is correct.
(a) Calculate the minimum uncertainty in momentum (expressed in MeV/?) for a proton confined to a nucleus of diameter 5.0 fm. (1 fm = 1 * 10-15 m). (b) A proton (rest mass 938.3 MeV/?2) in a nucleus of radius 6.0 fm has a kinetic energy of 5.6 MeV. If the proton were represented by a de Broglie wave, how many wavelengths could fit across the diameter of that nucleus? (1 fm = 1 * 10-15 m). (c) Electrons (rest mass 0.51 MeV/?2) moving with a speed of 1.60 × 105 m/s are described by a wave packet of width 2.65 nm. What range of values will most likely result from a measurement of the speed of the electrons? Please use:ℎ?              1240 eVnmℏ?              197 eVnm
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