(a) Explanation Write the expression for grating spacing. d = m λ sin θ Here, d is the grating spacing, m is the diffraction order and λ is the wavelength. The number of readings per centimeter is given by, N = 1 d Here, N is the number of readings. Replace d by m λ sin θ in the above expression. N = sin θ m λ Conclusion: Substitute 3 for m , 500 nm for λ and 32 ° for θ to get N (b) To determine The total number of primary maxima.

Bundle: Physics for Scientists and Engineers with Modern Physics, Loose-leaf Version, 9th + WebAssign Printed Access Card, Multi-Term

9th Edition

ISBN: 9781305932302

Author: Raymond A. Serway, John W. Jewett

Publisher: Cengage Learning

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Chapter 38, Problem 35P

(a)

To determine

The number of readings per centimeter.

(b)

To determine

The total number of primary maxima.

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Chapter 38, Problem 34P

Chapter 38, Problem 36P

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Light of wavelength 500 nm is incident normally on a diffraction grating. The third-order maximum of the diffraction pattern is observed at 32.0°. (a) What is the number of rulings per centimeter for the grating?answer in grooves/cm(b) Determine the total number of primary maxima that can be observed in this situation.

Light of wavelength 500 nm is incident normally on a diffraction grating. If the third-ordermaximum of the diffraction pattern is observed at 32.0°, (a) what is the number of rulings percentimeter for the grating? (b) Determine the total number of primary maxima that can beobserved in this situation. (N = 3,530 grooves/cm, 11 maxima)

(a) White light is spread out into its spectral components by a diffraction grating. If the grating has 1,970 grooves per centimeter, at what angle (in degrees) does red light of wavelength 640 nm appear in first order? (Assume that the light is incident normally on the gratings.) 7.35° (b) What If? What is the angular separation (in degrees) between the first-order maximum for 640 nm red light and the first-order maximum for blue light of wavelength 450 nm? °

Chapter 38 Solutions

Bundle: Physics for Scientists and Engineers with Modern Physics, Loose-leaf Version, 9th + WebAssign Printed Access Card, Multi-Term

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The number of readings per centimeter.

Solution Summary: The author explains the number of readings per centimeter and the expression for grating spacing.

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The number of readings per centimeter.

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Chapter 38 Solutions