Concept explainers
Refrigerant-134a at 400 psia has a specific volume of 0.1144 ft3/lbm. Determine the temperature of the refrigerant based on (a) the ideal-gas equation, (b) the van der Waals equation, and (c) the refrigerant tables.
(a)
The temperature of the refrigerant using the ideal gas equation.
Answer to Problem 95P
The temperature of the refrigerant using the ideal gas equation is
Explanation of Solution
Determine the temperature of the refrigerant using the ideal gas equation.
Here, the pressure of the refrigerant is
Conclusion:
Refer to Table A-1E to find the gas constant, the critical pressure, and the critical temperature of refrigerant-134a as
Substitue
Thus, the temperature of the refrigerant using the ideal gas equation is
(b)
The temperature of the refrigerant using the van der Waals.
Answer to Problem 95P
The temperature of the refrigerant using the van der Waals is
Explanation of Solution
Determine the temperature of the refrigerant using the van der Waals.
Here, the critical temperature is
Conclusion:
Substitute
Thus, the temperature of the refrigerant using the van der Waals is
(c)
The temperature of the refrigerant using the refrigerant table R-134.
Answer to Problem 95P
The temperature of the refrigerant using the refrigerant table R-134 is
Explanation of Solution
From the Table A-13E, “Superheated refrigrenat-134a” to obtain the value of the temperature of the refrigerant at
Unit conversion temperature from
Thus, the temperature of the refrigerant using the refrigerant table R-134 is
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Chapter 3 Solutions
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