Schaum's Outline of College Physics, Twelfth Edition (Schaum's Outlines)
Schaum's Outline of College Physics, Twelfth Edition (Schaum's Outlines)
12th Edition
ISBN: 9781259587399
Author: Eugene Hecht
Publisher: McGraw-Hill Education
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Chapter 39, Problem 14SP

Two thin lenses having focal lengths of +200 cm and –400 cm are glued together so as to have a common axis. Determine the dioptric power of the combination. Discuss the physics of your answer. [Hint: Go back to Eq. (38.4), and then study the definition of dioptric power.]

Expert Solution & Answer
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To determine

The dioptric power of the combination of two lenses when the focal length of lensesis +200 cm and 400 cm.

Answer to Problem 14SP

Solution:

0.25 D and the combination behaves as a convex lens of focal length 4 m.

Explanation of Solution

Given data:

The focal length of first lens is +200 cm.

The focal length of second lens is 400 cm.

Formula used:

Write the expression for the focal length of the combination of lenses in contact.

1F=1f1+1f2

Here, F is the focal length of the combination of lenses, f1 is the focal length of the first lens, and f2 is the focal length of the second lens.

Write the expression for power of the combined lens.

P=1F

Here, P is the power of the combined lens.

Explanation:

Recall the expression for the focal length of the combination of lenses in contact.

1F=1f1+1f2

Substitute +200 cm for f1 and 400 cm for f2

1F=1(+200 cm)(1 m100 cm)+1(400 cm)(1 m100 cm)=(12 m14 m)=14 m1F=4 m

Recall the expression for the power of the combined lens.

P=1F

Substitute 4 m for F

P=14 m=0.25 m11 D1 m1=0.25 D

When the lens of focal length +200 cm, that is a convex lens, and lens of focal length 400 cm, that is a concave lens, are kept in contact, the combination behaves as a convex lens of focal length 4 m. The power of the combination of lenses is 0.25 D.

Conclusion:

The dioptric power of combination of lenses is 0.25 D and the combination behaves as a convex lens of focal length 4 m.

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Convex and Concave Lenses; Author: Manocha Academy;https://www.youtube.com/watch?v=CJ6aB5ULqa0;License: Standard YouTube License, CC-BY