Fundamentals of Physics, Binder Ready Version
10th Edition
ISBN: 9781118230640
Author: Halliday, David; Resnick, Robert; Walker, Jearl
Publisher: WILEY
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Chapter 39, Problem 38P
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The amount of energy of the atom increase.
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A hydrogen atom transitions from the n = 8 excited state to the n = 4 excited state, emitting a photon.
(a) What is the energy, in electron volts, of the photon emitted by the hydrogen atom? eV(b) What is the wavelength of the photon emitted by the hydrogen atom? m(c) What is the frequency of the photon emitted by the hydrogen atom? Hz
A hydrogen atom emits a photon that has momentum 6.977 × 10-27 kg·m/s. This photon is emitted because the electron in the atom falls from a higher energy level into the n = 1 level. What is the quantum number of the level from which the electron falls? Use values of h = 6.626 × 10-34 J·s, c = 2.998 × 108 m/s, and e = 1.602 × 10-19 C.
An atom (not a hydrogen atom) absorbs a photon whose associated frequency is 6.2 * 1014 Hz. By what amount does the energy of the atom increase?
Chapter 39 Solutions
Fundamentals of Physics, Binder Ready Version
Ch. 39 - Prob. 1QCh. 39 - Prob. 2QCh. 39 - Prob. 3QCh. 39 - Prob. 4QCh. 39 - Prob. 5QCh. 39 - Prob. 6QCh. 39 - Prob. 7QCh. 39 - Prob. 8QCh. 39 - Prob. 9QCh. 39 - Prob. 10Q
Ch. 39 - Prob. 11QCh. 39 - Prob. 12QCh. 39 - Prob. 13QCh. 39 - Prob. 14QCh. 39 - Prob. 15QCh. 39 - Prob. 1PCh. 39 - Prob. 2PCh. 39 - Prob. 3PCh. 39 - Prob. 4PCh. 39 - Prob. 5PCh. 39 - Prob. 6PCh. 39 - Prob. 7PCh. 39 - Prob. 8PCh. 39 - Prob. 9PCh. 39 - Prob. 10PCh. 39 - Prob. 11PCh. 39 - Prob. 12PCh. 39 - Prob. 13PCh. 39 - Prob. 14PCh. 39 - Prob. 15PCh. 39 - Prob. 16PCh. 39 - Prob. 17PCh. 39 - Prob. 18PCh. 39 - Prob. 19PCh. 39 - Prob. 20PCh. 39 - Prob. 21PCh. 39 - Prob. 22PCh. 39 - Prob. 23PCh. 39 - Prob. 24PCh. 39 - Prob. 25PCh. 39 - Prob. 26PCh. 39 - Prob. 27PCh. 39 - Prob. 28PCh. 39 - Prob. 29PCh. 39 - Prob. 30PCh. 39 - Prob. 31PCh. 39 - Prob. 32PCh. 39 - Prob. 33PCh. 39 - Prob. 34PCh. 39 - Prob. 35PCh. 39 - Prob. 36PCh. 39 - Prob. 37PCh. 39 - Prob. 38PCh. 39 - Prob. 39PCh. 39 - Prob. 40PCh. 39 - Prob. 41PCh. 39 - Prob. 42PCh. 39 - Prob. 43PCh. 39 - Prob. 44PCh. 39 - Prob. 45PCh. 39 - Prob. 46PCh. 39 - Prob. 47PCh. 39 - Prob. 48PCh. 39 - Prob. 49PCh. 39 - Prob. 50PCh. 39 - Prob. 51PCh. 39 - Prob. 52PCh. 39 - Prob. 53PCh. 39 - Prob. 54PCh. 39 - Prob. 55PCh. 39 - Prob. 56PCh. 39 - Prob. 57PCh. 39 - Prob. 58PCh. 39 - Prob. 59PCh. 39 - Prob. 60PCh. 39 - Prob. 61PCh. 39 - Prob. 62PCh. 39 - Prob. 63PCh. 39 - Prob. 64PCh. 39 - A diatomic gas molcculc consistsof two atoms of...Ch. 39 - Prob. 66PCh. 39 - Prob. 67PCh. 39 - Prob. 68PCh. 39 - Prob. 69PCh. 39 - Prob. 70PCh. 39 - An old model of a hydrogen atom has the charge e...Ch. 39 - Prob. 72PCh. 39 - Prob. 73P
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- A hydrogen atom emits a photon that has momentum 6.813 × 10-27 kg⋅m/s. This photon is emitted because the electron in the atom falls from a higher energy level into the n = 1 level. What is the quantum number of the level from which the electron falls? Use values of h = 6.626 × 10-34 J·s, c = 2.998 × 108 m/s, and e = 1.602 × 10-1⁹ C. Number i 1 Bohr-model picture of photon emission Unitsarrow_forwardb. An electron and a photon has the same wavelength of 0.21 nm. Calculate the momentum and energy (in eV) of the electron and the photon. (Given c =3.00x108 m s-1, h =6.63 x 1034 J s, me=9.11 x 10-31 kg, mp=1.67 x 1027 kg and e=1.60x1019 C)arrow_forwardThe energy in eV of a photon, if the frequency of the radiation is 7 × 10¹ Hz is 4.0 eV 3.9 eV (a) (c) (b) 2.9 eV (d) 1.9 eVarrow_forward
- An alpha particle (m = 6.64 × 10−27 kg) emitted in the radioactive decay of Uranium-238 has an energy of 4.20 MeV. What is its de Broglie wavelength?arrow_forwardA mercury atom emits light at many wavelengths, two of which are at (1) 404.7 nm and (2) 435.8 nm . Both of these transitions are to the same final state. Determine the energy of each emitted wavelength (in J). A E1 = 7.908 x 10-19 J and E2 = 6.558 x10-19 J E1 = 4.628 x 10-19 J and E2 = 4.968 x10-19 J E1 = 5.908 x 10-19 J and E2 = 5.558 x10-19J E1 = 4.908 x 10-19 J and E2 = 4.558 x10-19 Jarrow_forwardWhat are the (a) energy, (b) magnitude of the momentum, and (c) wavelength of the photon emitted when a hydrogen atom undergoes a transition from a state with n = 4 to a state with n = 2? (a) Number 2.55 Units eV (b) Number 1.3617 Units kg-m/s or N-s (c) Number 4.865976353 Units This answer has no unitsarrow_forward
- A metal absorbing a photon with energy 6.00 eV emits an electron that carries an initial kinetic energy = 1.03 eV. If the metal absorbs another photon with energy 12.0 eV and emits an electron, what is the initial kinetic energy of the emitted electron (in eV)?arrow_forwardAn atom (not a hydrogen atom) absorbs a photon whose associated wavelength is 375 nm and then immediately emits a photon whose associated wavelength is 580 nm. How much net energy in eV is absorbed by the atom in this process.arrow_forwardAn X-ray photon with a wavelength of 0.999 nmnm strikes a surface. The emitted electron has a kinetic energy of 990 eV. What is the binding energy of the electron in kJ/molkJ/mol? [Note that KEKE = 12mv212mv2 and 1 electron volt (eVeV) = 1.602×10−19J1.602×10−19J.] Express your answer using three significant figures.arrow_forward
- QUESTION 1 A photon emitted by a blackbody has an energy of 1.021 J. What is the frequency of such a photon?(h=6.63.10-34 J.s) QUESTION 2 What is the energy (in eV) of a gamma-ray photon with frequency f=5.67-102¹ Hz? (h=4.136-10-15eV/Hz) QUESTION 3 The ground level of the hydrogen atom has an energy E,= 13.6 eV while the first excited state has an energy Calculate the energy difference of an electron going from the first excited state back to the ground state. 1 QUESTION 4 What is the frequency of the photon emitted by the electron in Question 3? QUESTION 5 E 2= -3.4 eV. An electron has a wavelength of 0.267 nm (1 nm = 10-9 m). What is the speed of such electron orbiting the nucleus? ( m=9.11-10-31 kg)arrow_forwardAn excited electron drops to its ground state, emitting a photon of frequency f = 5.10×1015 Hz. What is the energy of this photon? Enter the numerical value in units of eV.arrow_forwardWhat is the energy of a photon of frequency 3.30 × 1014 Hz? (h = 6.626 × 10−34 J⋅s)arrow_forward
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