University Physics with Modern Physics, Volume 2 (Chs. 21-37); Mastering Physics with Pearson eText -- ValuePack Access Card (14th Edition)
14th Edition
ISBN: 9780134265414
Author: Hugh D. Young, Roger A. Freedman
Publisher: PEARSON
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Question
Chapter 39, Problem 39.38E
(a)
To determine
The wavelength corresponding to the peak of the planck distribution.and frequency corresponding to
(b)
To determine
The wavelength corresponding to the peak of the planck distribution.and frequency corresponding to
(c)
To determine
The wavelength corresponding to the peak of the planck distribution.and frequency corresponding to
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Determine lm , the wavelength at the peak of the Planck distribution, and the corresponding frequency ƒ, at these temperatures: (a) 3.00 K; (b) 300 K; (c) 3000 K.
Problem-1:
An asteroid is hurtling toward earth at 150,000“. The temperature of the asteroid is about 100 K, meaning that its peak emission
is 2 = 29 µm. The speed of light is c =
3E[8].
a) What is the wavelength of light that we receive from the asteroid? (Answer: 2.89855E[-05] m)
The energy emitted by a black body's surface per unit area at a particul ar wavelength can
be calcul ated using Planck's Radiation Law, which can be written as follows,
2nhc?
E(2, T) =
25. (ehc/kT -1)
where his Planck's constant 6.626 x 10-27 erg.s, c is the speed oflight, kis the Boltzmann
constant = 1.38 x 10-18 erg/K, Tis the temperature in Kelvins and A is the wavelength in
um.
If E is given in erg/um?, what are the units of the constant 2n, given that the equation is
valid and therefore dimensionally homogenous? If the speed of light is 3.00x10$ m/s, what
value and unit should be used for c in this equation to maintain dimensional homogeneity?
Note: erg is a unit of energy equal to 10-7 Joules and the whole expression
(ehc/AkT – 1) ends up dimensionless.
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Chapter 39 Solutions
University Physics with Modern Physics, Volume 2 (Chs. 21-37); Mastering Physics with Pearson eText -- ValuePack Access Card (14th Edition)
Ch. 39.2 - Prob. 39.2TYUCh. 39.3 - Prob. 39.3TYUCh. 39.4 - Prob. 39.4TYUCh. 39.5 - Prob. 39.5TYUCh. 39.6 - Prob. 39.6TYUCh. 39 - Prob. 39.1DQCh. 39 - Prob. 39.2DQCh. 39 - Prob. 39.3DQCh. 39 - When an electron beam goes through a very small...Ch. 39 - Prob. 39.5DQ
Ch. 39 - Prob. 39.6DQCh. 39 - Prob. 39.7DQCh. 39 - Prob. 39.8DQCh. 39 - Prob. 39.9DQCh. 39 - Prob. 39.10DQCh. 39 - Prob. 39.11DQCh. 39 - Prob. 39.12DQCh. 39 - Prob. 39.13DQCh. 39 - Prob. 39.14DQCh. 39 - Prob. 39.15DQCh. 39 - Prob. 39.16DQCh. 39 - Prob. 39.17DQCh. 39 - Prob. 39.18DQCh. 39 - Prob. 39.19DQCh. 39 - Prob. 39.20DQCh. 39 - Prob. 39.21DQCh. 39 - When you check the air pressure in a tire, a...Ch. 39 - Prob. 39.1ECh. 39 - Prob. 39.2ECh. 39 - Prob. 39.3ECh. 39 - Prob. 39.4ECh. 39 - Prob. 39.5ECh. 39 - Prob. 39.6ECh. 39 - Prob. 39.7ECh. 39 - Prob. 39.8ECh. 39 - Prob. 39.9ECh. 39 - Prob. 39.10ECh. 39 - Prob. 39.11ECh. 39 - Prob. 39.12ECh. 39 - Prob. 39.13ECh. 39 - Prob. 39.14ECh. 39 - Prob. 39.15ECh. 39 - Prob. 39.16ECh. 39 - Prob. 39.17ECh. 39 - Prob. 39.18ECh. 39 - Prob. 39.19ECh. 39 - Prob. 39.20ECh. 39 - Prob. 39.21ECh. 39 - Prob. 39.22ECh. 39 - Prob. 39.23ECh. 39 - Prob. 39.24ECh. 39 - Prob. 39.25ECh. 39 - Prob. 39.26ECh. 39 - Prob. 39.27ECh. 39 - Prob. 39.28ECh. 39 - Prob. 39.29ECh. 39 - Prob. 39.30ECh. 39 - Prob. 39.31ECh. 39 - Prob. 39.32ECh. 39 - Prob. 39.33ECh. 39 - Prob. 39.34ECh. 39 - Prob. 39.35ECh. 39 - Prob. 39.36ECh. 39 - Prob. 39.37ECh. 39 - Prob. 39.38ECh. 39 - Prob. 39.39ECh. 39 - Prob. 39.40ECh. 39 - Prob. 39.41ECh. 39 - Prob. 39.42ECh. 39 - Prob. 39.43ECh. 39 - Prob. 39.44ECh. 39 - Prob. 39.45ECh. 39 - Prob. 39.46ECh. 39 - Prob. 39.47ECh. 39 - Prob. 39.48ECh. 39 - Prob. 39.49ECh. 39 - Prob. 39.50PCh. 39 - Prob. 39.51PCh. 39 - Prob. 39.52PCh. 39 - Prob. 39.53PCh. 39 - Prob. 39.54PCh. 39 - Prob. 39.55PCh. 39 - Prob. 39.56PCh. 39 - Prob. 39.57PCh. 39 - Prob. 39.58PCh. 39 - Prob. 39.59PCh. 39 - An Ideal Blackbody. A large cavity that has a very...Ch. 39 - Prob. 39.61PCh. 39 - Prob. 39.62PCh. 39 - Prob. 39.63PCh. 39 - Prob. 39.64PCh. 39 - Prob. 39.65PCh. 39 - Prob. 39.66PCh. 39 - Prob. 39.67PCh. 39 - Prob. 39.68PCh. 39 - Prob. 39.69PCh. 39 - Prob. 39.70PCh. 39 - Prob. 39.71PCh. 39 - Prob. 39.72PCh. 39 - Prob. 39.73PCh. 39 - Prob. 39.74PCh. 39 - Prob. 39.75PCh. 39 - Prob. 39.76PCh. 39 - Prob. 39.77PCh. 39 - Prob. 39.78PCh. 39 - Prob. 39.79PCh. 39 - Prob. 39.80PCh. 39 - A particle with mass m moves in a potential U(x) =...Ch. 39 - Prob. 39.82PCh. 39 - Prob. 39.83PCh. 39 - DATA In the crystallography lab where you work,...Ch. 39 - Prob. 39.85PCh. 39 - Prob. 39.86CPCh. 39 - Prob. 39.87CPCh. 39 - Prob. 39.88PPCh. 39 - Prob. 39.89PPCh. 39 - Prob. 39.90PPCh. 39 - Prob. 39.91PP
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- 8πhy3 dv (a) Express the Planck radiation formula, Edv = c3 ehv/kT-1' terms of λ (and dλ), namely Edλ. (b) Solved=0 for λ = Amax in to determine the value of maxT in m-K, where max is the wavelength at which the blackbody spectrum has its maximum value at a given temperature T.arrow_forwardNotation: (i) A vector is denoted by a bold letter, e.g., E(1) is a time-dependent vector. (ii) A unit vector is identified by a ^ sign, e.g., â, is a unit vector along the z-axis. Physical constants: Planck's constant, h = 6.626 × 10-34 m² kg s-I Boltzmann's constant, k = 1.38 × 10-23 m² kg s-² K-' Speed of light in vacuum, c = 3 × 10% m s-! Permittivity of vacuum, & = 8.854 × 10-12 F/m Permeability of vacuum, flo=4r × 10-’ H/m Electron charge, q = 1.602 ×10-19 C EEE/ELEC2347/ page 2 of 6 1. (a) As shown in Fig. la, the object and the screen is separated by l = 100cm. When we put a convex lens in the middle point between the object and the screen, a clear image is formed on the screen. What is the focal length of the lens? You may use either ABCD matrix or other methods. 100cm Fig. laarrow_forwardPlanck's principal assumption was that the energies of the electronic oscillators can have only the values &n=nhv and that Aε = hv. (a) Further assume that the number of oscillators with the energy En, Nn, is proportional to e-En/kT at the temperature T, namely Nn xe-En/kT, where N is the total number of oscillators. Show N that the average energy per oscillator is ɛ̃ = formula, Edv = formula as v → 0. ΣNnEn N c3 ehv/kT-1' = (b) As v→ 0, then Aɛ → 0 and & is essentially continuous. Hence, we should expect the non-classical Planck distribution to go over to the classical Rayleigh-Jeans distribution at low frequencies, where Ac→ 0. Show that the Planck radiation 8πhy3 dv reduces to the Rayleigh-Jeans hv ehv/kT-1arrow_forward
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- Consider a black body of surface area 22.0 cm² and temperature 5700 K. (a) How much power does it radiate? 131675.5 W (b) At what wavelength does it radiate most intensely? 508.421 nm (c) Find the spectral power per wavelength at this wavelength. Remember that the Planck intensity is "intensity per unit wavelength", with units of W/m³, and "power per unit wavelength" is equal to that intensity times the surface area, with units of W/m 131.5775 Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. W/marrow_forwardPlanck’s constant has the value h = 6.626 × 10–34 joule-seconds (J-s), and the speed of light is c = 3 × 108 m/s. Using these values, calculate the wavelength carried by photons emitted with an energy of 1.1 × 10-19 J. Pick the closest value:arrow_forwardThe kilogram has been redefined based on Planck's constant (h) and a sphere of pure crystalline silicon: 8AsiVsphere Msphere = 2h 13 ст-а? The terms (with their relative uncertainties) are: (1) Planck's constant h (zero uncertainty as it is defined exactly); (2) the bracketed term including accurately known Rydberg constant R, speed of light c, mass of electron (me), and fine structure constant a, with a combined uncertainty of +4.7 × 10-8%; (3) atomic mass Asi for the 28 Si-enriched silicon (+5.4 x 10-7%); (4) volume of the Si sphere (+2.0 × 10-6%) and (5) crystal lattice parameter I (+1.84 x 10-7%). There are exactly eight atoms per unit cell in the sphere. Compute the relative uncertainty of myphere- To find the uncertainty of l, use the function y = x“, for which the uncertainty is propagated using %e, = a(%e,). relative uncertainty of msphere: % The mass of the sphere of pure silicon (999.698 336 5 g) must also be corrected for defects in the crystal lattice ( mdefects = 3.8…arrow_forward
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