Physics for Scientists and Engineers with Modern Physics
10th Edition
ISBN: 9781337553292
Author: Raymond A. Serway, John W. Jewett
Publisher: Cengage Learning
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Question
Chapter 39, Problem 47CP
(a)
To determine
How the photoelectrons would produce.
(b)
To determine
The work function for the metal.
(c)
To determine
The maximum kinetic energy of the photoelectrons.
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a. The kinetic energy of an electron is (0+1.5)keV. Find the de Broglie wavelength and momentum of the electron.
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C. Discuss (in your own words) why the Saturation Current is directly proportional to the Intensity of incident radiation in the Photoelectric Effect.
In a photoelectric experiment using a photocell, the graph of stopping potential Vs against frequency f of incident light as shown in FIGURE 6 is obtained. From the graph, deduce
(i) the threshold frequency.
(ii) the value of maximum kinetic energy when incident light frequency is 5.0✕1014 Hz. (Given: h=6.63✕10-34 Js ; e=1.602✕10-19 C).
(iii) Determine the value of stopping potential Vs. (Given: h=6.63✕10-34 Js ; e=1.602✕10-19 C)
A photon with an energy of 2.24 eV strikes a photoemissive surface whose work function is 1.57 eV. Calculate the threshold frequency for the surface.
1.68 E 14 Hz 3.79 E 14 Hz 5.04 E 14 Hz 7.25 E 14 Hz
Chapter 39 Solutions
Physics for Scientists and Engineers with Modern Physics
Ch. 39.1 - Prob. 39.1QQCh. 39.2 - Prob. 39.2QQCh. 39.2 - Prob. 39.3QQCh. 39.2 - Prob. 39.4QQCh. 39.3 - Prob. 39.5QQCh. 39.5 - Prob. 39.6QQCh. 39.6 - Prob. 39.7QQCh. 39 - Prob. 1PCh. 39 - Prob. 2PCh. 39 - Prob. 3P
Ch. 39 - Prob. 4PCh. 39 - Prob. 5PCh. 39 - Prob. 6PCh. 39 - Prob. 8PCh. 39 - Prob. 9PCh. 39 - Prob. 10PCh. 39 - Prob. 11PCh. 39 - Prob. 12PCh. 39 - Prob. 13PCh. 39 - Prob. 15PCh. 39 - Prob. 16PCh. 39 - Prob. 17PCh. 39 - Prob. 18PCh. 39 - Prob. 19PCh. 39 - Prob. 20PCh. 39 - Prob. 22PCh. 39 - Prob. 23PCh. 39 - Prob. 24PCh. 39 - Prob. 25PCh. 39 - Prob. 26PCh. 39 - Prob. 27PCh. 39 - Prob. 30PCh. 39 - Prob. 31PCh. 39 - Prob. 32PCh. 39 - Prob. 33PCh. 39 - Prob. 35PCh. 39 - Prob. 37PCh. 39 - Prob. 38PCh. 39 - Prob. 39PCh. 39 - Prob. 40APCh. 39 - Prob. 41APCh. 39 - Prob. 43APCh. 39 - Prob. 44APCh. 39 - Prob. 45APCh. 39 - Prob. 46APCh. 39 - Prob. 47CPCh. 39 - Prob. 48CPCh. 39 - Prob. 49CPCh. 39 - Prob. 50CP
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- Photoelectrons are ejected from a photo electrode and are detected at a distance of 2.50 cm away from the photoelectrical. The work function of the photo electrode is 2.71 eV and the incident radiation has a wavelength of 420 nm. How long does it take a photoelectron to travel to the detector?arrow_forwardIn the photoelectric effect, explain why the stopping potential depends on the frequency of the light but not on the intensity.arrow_forwardWhen monochromatic light of an unknown wavelength falls on a sample of aluminum, a minimum potential of 2.45 V is required to stop all of the ejected photoelectrons. (The work function for aluminum is 4.08 eV.) (a) Determine the maximum kinetic energy (in eV) of the ejected photoelectrons. eV (b) Determine the maximum speed (in m/s) of the ejected photoelectrons. m/s (c) Determine the wavelength in nm of the incident light. nmarrow_forward
- How does Einstein’s explanation account for each of these characteristics of the photoelectric effect?a. The photoelectric current is zero for frequencies below some threshold.b. The photoelectric current increases with increasing light intensity.c. The photoelectric current is independent of ΔV for ΔV ≥ 1 V.d. The photoelectric current decreases slowly as ΔV becomes more negative.e. The stopping potential is independent of the light intensity.Which of these cannot be explained by classical physics? Explain.arrow_forwardDuring the photoelectric effect experiment, a photon is emitted with 9.60 x10-20 J of kinetic energy. If the work function of the photosensitive surface is 1.68 eV, which is the frequency of the incident light? (h = 6.626 x 10-34 J-s; 1 eV = 1.60 x 10-19 J)arrow_forwardIn a photoelectric-effect experiment, the intensity of the light is increased while the frequency, which is above the threshold frequency, is held constant. As a result,A. There are more electrons. B. The electrons are faster.C. Both A and B. D. Neither A nor B.arrow_forward
- In the photoelectric effect (for a given target and a given frequency of the incident light), which of these quantities, if any, depend on the intensity of the incident light beam: (a) the maximum kinetic energy of the electrons, (b) the maximum photoelectric current, (c) the stopping potential, (d) the cutoff frequency?arrow_forwardA photon with an energy of 2.24 eV strikes a photoemissive surface whose work function is 1.57 eV. Calculate the maximum kinetic energy of the ejected photoelectron. a 0.67 eV b 3.81 eV c 4.69 eV d 5.07 eVarrow_forwardThe work function of a certain material is 4.9 eV. What is the photoelectric minimum (threshold) frequency for this material? A. 1.18 x 1015 Hz B. 2.23 x 1015 Hz C. 9.01 x 1014 Hz D. 3.48 x 1015 Hz E. 2.56 x 1015 Hzarrow_forward
- In compton scattering, the photon transfers some of its energy to the electron, while scattering with its remaining energy. Why is this phenomenon not transferred to the electron but absorbed in the photoelectric effect?arrow_forwardThe work function of tungsten is 4.5 eV. What is the photoelectric threshold wavelength for tungsten? What type of radiation is this? h = 4.136 x 10-15 eV.s c = 3.0 x 108 m/sarrow_forwardThe work function for titanium is 4.33 eV. (a) Convert the value of the work function from electron volts to joules. J(b) Find the cutoff frequency for titanium. Hz(c) What maximum wavelength of light incident on titanium releases photoelectrons from the titanium's surface? nm(d) If light of energy 8.32 eV is incident on titanium, what is the maximum kinetic energy of the ejected photoelectrons? Give the answer in electron volts. eV(e) For photons of energy 8.32 eV, what stopping potential would be required to arrest the current of photoelectrons? Varrow_forward
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