How maximum volume of urea solution with a concentration of 1.25 M can be obtained from three given source must be explained. What is the maximum volume obtainable must also be shown. Concept introduction: If the strength is increased, then volume decreases. If the concentration decreases, then volume increases. From the volume and strength of a given solution milimole can be calculated as follows: m m = V × S Here, mm is milimole,V is volume of the solution in ml and S is strength of the solution in molarity Thus both volume and strength of a solution is inversely proportional with mmol of the solution.

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Chapter 4, Problem 125IAE

Interpretation Introduction

Interpretation:

How maximum volume of urea solution with a concentration of 1.25 M can be obtained from three given source must be explained. What is the maximum volume obtainable must also be shown.

Concept introduction:

If the strength is increased, then volume decreases. If the concentration decreases, then volume increases.

From the volume and strength of a given solution milimole can be calculated as follows:

mm=V×S

Here, mm is milimole,V is volume of the solution in ml and S is strength of the solution in molarity

Thus both volume and strength of a solution is inversely proportional with mmol of the solution.

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