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A truss is a Structure made of members joined at their ends. For the truss shown in the figure, the forces in the seven members are determined by solving the following system of seven equations.
F1cos28.5°+ F2-3000=0,
F1sin 28.5°+6521=0,
- F1cos 28.5°-F3cos 58.4°+ F5cos 58.4°+ F6cos 28.5°+3000 =0,
-F1sin 28.5°- F3sin 58.4°- F6sin 58.4 °- F6sin 28.5°=0
-F4- F5cos 58.4°+ F7=0, F6sin 28.5°+7479=0- F7- F6cos 28.5°=0 Write the equations in matrix form and use MATLAB to determine the forces in the members. A positive force means tensile force and a negative force means compressive force. Display the results in a table where the first column displays the member number and the second column displays the corresponding force.
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Chapter 4 Solutions
EBK MATLAB: AN INTRODUCTION WITH APPLIC
- Question 1 A ferromagnetic core with a relative permeability of 1500 is shown in Figure 2. The dimensions are as shown in the diagram, and the depth of the core is 7 cm. The air gaps on the left and right sides of the core are 0.070 and 0.020 cm, respectively. Because of fringing effects, the effective area of the air gaps is 5 percent larger than their physical size. If there are 400 turns in the coil wrapped around the center leg of the core and if the current in the coil is 1.0 A, what is a) the flux in each of the left, center, and right legs of the core? b) the flux density in each air gap? 7 cm ст ст 30 cm 30 cm 7 cm 400 turns 0.05 cm 30 cm 0.07 cm 7 cm Core depth = 7 cm Figure 2arrow_forwardA squara magnotic core has e moan path length 55:m and x-sactional eres of 150zm*A 200 turns coil of wire is wrapped around one leg of the core. The core is made of the materia' having relative permeability 3980. Find • Fow much current is required to produce 0.012 Wb of flux in the cere • Celculate the reluctance and megnetomotive farce.arrow_forwardQ3/A) A 1000-VA 230/115-V transformer bas been tested to determine its equivalent circun. The results of the tests are shown below. Open-circuit test Short-circuit test Foc-230 V 19.1 V Joc=0.45 A Isc 8.7 A Poc= 30 W P=42.3 W All data given were taken from the primary side of the transformer. (a) Find the equivalent circuit of this transformer referred to the low-voltage side of the transformer. (b) Determine the transformer's efficiency at rated conditions and 0.8 PF lagging.arrow_forward
- Quèstion 14 The point form of Ampere law is given by Curl(D) = J Curl(V) = I Curl(B) = I Curl(H) = J P Type here to searcharrow_forwardProblem 5 Consider a three winding transformer with the following particulars: = Z₁ Z2 Z3 =0.02 + j0.08 £, V₂ = 400 V, 12 = 60/30° A, and I3 = 50/-40° A. Assume that V₂ is the reference phasor, calculate: The intermediate voltage Vo. a. b. The primary current I₁ and the primary voltage V₁. c. The tertiary voltage V3 referred to the primary side. d. The apparent powers and the power factors at the primary, secondary and tertiary terminals. e. The transformer efficiency.arrow_forwardTYDDIAD I Q4-(A)-draw the phasor diagram of the transformer at full load with inductive loadarrow_forward
- Figure Q1 shows a transformer core that has the primary winding (Np) of 500 turns and second winding (N3) of 250 turns. The absolute permeability (uo) is 47x10-7 H/m. Ignore the leakage flux. Illustrate how the relative permeability of the iron core would change with the primary current Ip and secondary current Is. Core Primary Winding Secondary Winding 20 cm N=500 turns 40 cm N,-250 turns 40 cm 20 cm 20 cm 20 cm Depth of Core=30 cm Leakage Flux Main Flux Figure Q1: Transformer core 4444444Aarrow_forwardQuestion: 01 A two-legged core is shown in figure below. The winding on the left leg of the core (N) has 800 turns. The depth of the core is 15 cm. The small airgap is 0.05 cm and there is no fringing effect. If the dimensions are as shown, then determine the total reluctance of the given core when u, =800 and constant. 15cm 25cm 10cm 10cm 50cm N=800 5cmarrow_forwardMatch the following: (i) Hysteresis loss (a) Can be redud by constructing the core with laminated sheets of alloy steel (ii) Eddy current loss (b) Can be reduced by the use of special high grades of alloy stl as core material.arrow_forward
- what is the curlarrow_forwardconstant. 15 cm core depth = 15 cm Problem 2 A ferromagnetic core with a relative permeability of 2000 is shown in Figure. The dimensions are as shown in the diagram, and the depth of the core is 7 cm. The air gaps on the left and right sides of the core are 0.050 and 0.070 cm, respectively. If there are 300 turns in the coil wrapped around the center leg of the core and if the current in the coil is 1.0 A, what is the flux in each of the left, center, and right legs of the core? What is the flux density in each air gap? |7 cm 30 cm 7 cm 7 cm 30 cm 7 cm 30 cm -0,05 cm 300 turns 0.07 cm 7 cm 1|Pagearrow_forwarduse kirchhoffs Junction rule and loop rule to solve for currents I1 , I2 and I3..arrow_forward
- Power System Analysis and Design (MindTap Course ...Electrical EngineeringISBN:9781305632134Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. SarmaPublisher:Cengage Learning
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