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The net heat exchange by radiation from plate 1 with radius b to plate 2 with radius athat are separated by a distance c is given by:
where
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Chapter 4 Solutions
EBK MATLAB: AN INTRODUCTION WITH APPLIC
- Consider a sinusoidal current i-Icos(15[rad/s] t). Its current phasor makes an angle 135⁰ with the horizontal. Assuming the phasor has not completed a half revolution and was lying on the +x-axis at t=0, what is the time elapsed since the current first reached its maximum value? A. 0.050[S] B. 0.16 [s] C. 0.32[s] D. 9.0[s] 135°arrow_forward9. Calculate the capacitance between two parallel plates each of which is 100 cm? and 2 mm apart in air. a. 0.443 uµF b. 0.515 μμ c . 0.452 μμ F d. 0.502 μμF 10. Calculate the magnitude of the electric field at a point that is 30 cm from a point charge Q = -3.2 x 10-6 C. a. 3.2 x 10-6 N/C b. 3.0 x 105 N/C c. 2.8 x 10°N/C d. 2.4 x 105 N/Carrow_forwardThe sides measure 10.0cm in length each, what is the magnitude of the electric feild in the center of the square? Hint... The answer will be 3.?? x 10^-5 N/Carrow_forward
- Displacement current is taken to be negligible (compared to the conduction current) if ......... σ KWE 0 >WE O 0=0arrow_forwardFind the Electric Field Intensity at P (4, 2, -8) due to rho L1 = 40nC / m along the x-axis and rho L2 = 40nC / m along the y-axisarrow_forwardPlane z= 10 m carries charge 20nCim?. The electric field intensity at the origin is (a) 10n a, Vim (b) 18n a. Vim (c) 72n a. V/m (d) 360m a, Vimarrow_forward
- amazing explanation i just have two inquiries, to find the angle is it always -tan^-1(w/3)? or does it vary depedning on the equation? and if it varies what is the general equation for it? and the second is for the magnitude. same thing is it always 6/radical(w^2 +9) or it depends on each case? and if so also please give the general equation with an explanation, thank you! DO NOT REPEAT THE QUESTION JUST ANSWER THESE INQUIRIES PLEASE AND THANK YOU.arrow_forwardGraph: Take a graph sheet and divide it into 4 equal parts. Mark origin at the center of the graph sheet. Now mark +ve X-axis as Vf, -ve X-axis as Vr, +ve Y-axis as Ifand –ve Y-axis as Ir. Mark the readings tabulated for Si forward biased condition in first Quadrant and Si reverse biased condition in third Quadrant.arrow_forwardAssume that R₁ > R₂ and rank the segments according to the magnitude of the average electric field in them, greatest first. HA R₂ R₁ mm |a|b|c|d|e| O a. b=d> a = c = e O b. a>b>c>d>e O c. a = c = e = e> b=d O d. b> d > a = c = e O e. a = b = c = d = earrow_forward
- Consider a closed triangular box resting within a horizontal electric field of magnitude E = 6.86 × 104 N/C as shown in the figure below. 30.0 cm A closed right triangular box with its vertical side on the left and downward slope on the right rests within a horizontal electric field vector E that points from left to right. The box has a height of 10.0 cm and a depth of 30.0 cm. The downward slope of the box makes an angle of 60 degrees with the vertical. (a) Calculate the electric flux through the vertical rectangular surface of the box. kN • m?/c (b) Calculate the electric flux through the slanted surface of the box. kN • m?/c (c) Calculate the electric flux through the entire surface of the box. kN • m2/carrow_forwardTake a graph sheet and divide it into 4 equal parts. Mark origin at the center of the graph sheet. Now mark +ve X-axis as Vf, -ve X-axis as Vr, +ve Y-axis as Ifand –ve Y-axis as Ir. Mark the readings tabulated for Si forward biased condition in first Quadrant and Si reverse biased condition in third Quadrant.arrow_forwardQ8\ Determine the fifth roots of 2 – j5 in polar coordinates.arrow_forward
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