PHYSICS F/SCIEN.+ENGRS. W/SAPLING >IC<
6th Edition
ISBN: 9781319336127
Author: Tipler
Publisher: MAC HIGHER
expand_more
expand_more
format_list_bulleted
Concept explainers
Videos
Question
Chapter 4, Problem 26P
To determine
The experimental method to determine the force on one of the spring of the known weight of several persons and then use the method to determine the force constant of the car.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
An another object is in the outer space. Only three forces are acting on it. One has the magnitude of 9 N. The second one is perpendicular to the first one and has the magnitude of 12 N. Find the magnitude of the third force, if the object is in equilibrium. Draw the picture that shows all the forces.
Needs Complete typed solution with 100 % accuracy.
A 29.0-kg box is released on a 28 degree incline and accelerates down the incline at 0.26 m/s.
Find the friction force impeding its motion.
Express your answer to two significant figures and include the appropriate units.
Determine the coefficient of kinetic friction.
Express your answer using two significant figures.
A heavy object of mass m is located on an inclined ramp that is unpolished. The ramp makes an angle θ with the horizontal, and the heavy object has come to and remains at rest against a spring with spring constant k that is compressed by a distance d from its neutral position.
From the options offered, check all of the forces that should appear on the free body diagram of the heavy object.
A force due to kinetic friction acting on the inclined ramp due to the heavy object.
A force due to static friction acting on the inclined ramp due to the heavy object.
The weight of the spring.
A force due to static friction acting on the heavy object due to the inclined ramp.
The weight of the heavy object.
A force due to kinetic friction acting on the heavy object due to the inclined ramp.
A spring force, also known as an elastic force.
A normal force on the heavy object due to the inclined ramp.
A normal force on the inclined ramp due to the heavy object.
Chapter 4 Solutions
PHYSICS F/SCIEN.+ENGRS. W/SAPLING >IC<
Ch. 4 - Prob. 1PCh. 4 - Prob. 2PCh. 4 - Prob. 3PCh. 4 - Prob. 4PCh. 4 - Prob. 5PCh. 4 - Prob. 6PCh. 4 - Prob. 7PCh. 4 - Prob. 8PCh. 4 - Prob. 9PCh. 4 - Prob. 10P
Ch. 4 - Prob. 11PCh. 4 - Prob. 12PCh. 4 - Prob. 13PCh. 4 - Prob. 14PCh. 4 - Prob. 15PCh. 4 - Prob. 16PCh. 4 - Prob. 17PCh. 4 - Prob. 18PCh. 4 - Prob. 19PCh. 4 - Prob. 20PCh. 4 - Prob. 21PCh. 4 - Prob. 22PCh. 4 - Prob. 23PCh. 4 - Prob. 24PCh. 4 - Prob. 25PCh. 4 - Prob. 26PCh. 4 - Prob. 27PCh. 4 - Prob. 28PCh. 4 - Prob. 29PCh. 4 - Prob. 30PCh. 4 - Prob. 31PCh. 4 - Prob. 32PCh. 4 - Prob. 33PCh. 4 - Prob. 34PCh. 4 - Prob. 35PCh. 4 - Prob. 36PCh. 4 - Prob. 37PCh. 4 - Prob. 38PCh. 4 - Prob. 39PCh. 4 - Prob. 40PCh. 4 - Prob. 41PCh. 4 - Prob. 42PCh. 4 - Prob. 43PCh. 4 - Prob. 44PCh. 4 - Prob. 45PCh. 4 - Prob. 46PCh. 4 - Prob. 47PCh. 4 - Prob. 48PCh. 4 - Prob. 49PCh. 4 - Prob. 50PCh. 4 - Prob. 51PCh. 4 - Prob. 52PCh. 4 - Prob. 53PCh. 4 - Prob. 54PCh. 4 - Prob. 56PCh. 4 - Prob. 57PCh. 4 - Prob. 58PCh. 4 - Prob. 59PCh. 4 - Prob. 60PCh. 4 - Prob. 61PCh. 4 - Prob. 62PCh. 4 - Prob. 63PCh. 4 - Prob. 64PCh. 4 - Prob. 65PCh. 4 - Prob. 66PCh. 4 - Prob. 67PCh. 4 - Prob. 68PCh. 4 - Prob. 69PCh. 4 - Prob. 70PCh. 4 - Prob. 71PCh. 4 - Prob. 72PCh. 4 - Prob. 73PCh. 4 - Prob. 74PCh. 4 - Prob. 75PCh. 4 - Prob. 76PCh. 4 - Prob. 77PCh. 4 - Prob. 78PCh. 4 - Prob. 79PCh. 4 - Prob. 80PCh. 4 - Prob. 81PCh. 4 - Prob. 82PCh. 4 - Prob. 83PCh. 4 - Prob. 84PCh. 4 - Prob. 85PCh. 4 - Prob. 86PCh. 4 - Prob. 87PCh. 4 - Prob. 88PCh. 4 - Prob. 89PCh. 4 - Prob. 90PCh. 4 - Prob. 91PCh. 4 - Prob. 92PCh. 4 - Prob. 93PCh. 4 - Prob. 94PCh. 4 - Prob. 95PCh. 4 - Prob. 96PCh. 4 - Prob. 97PCh. 4 - Prob. 98P
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- The image below depicts the Apollo 16 Lunar Module (LM) on the moon's surface. The diagram to the right is a model of one of the four landing gear assemblies. Determine the force supported by members AB, AC, and AD under the assumption that the weight of the LM is uniformly distributed by all four landing gear assemblies. Use Mathematica or an online calculator such as the WolframAlpha 3 Equation System Solver to solve the 3 x 3 system of equations that you will end up with. Z NASA X A (2.5, 2.5, -2.2) m B (1.5, 1.5,0) m C(2, 1,-1.2) m D(1,2,-1.2) m B Darrow_forwardCalculate the forces in members BC, BE, and EF. Solve for each force from an equilibrium equation which contains that force as the only unknown. The forces are positive if in tension, negative if in compression. 3.0 m BC= Answers: BE= A 3.0 m EF= G i i i B 3.0 m 3.0 m F 1.9 m E 3.0 m 20.0 KN KN KN kN Darrow_forwardIf the values for frictional force are given: 8.83, 9.81, 11.77, 12.76 and 14.72 and for normal:16.68, 19.62, 22.56, 25.51 and 28.45 respectively. 1. Plot a graph for frictional force versus normal force. Be sure to label both x and y axes with the correct scale and units. 2. Draw a line of best fit for the curve.arrow_forward
- Problem A block of mass m is placed on a rough surface inclined relative to the horizontal. The incline angle is increased until the block start to move. Show that you can obtain the coefficient of static friction Ps by measuring the critical angle e where slipping occurs. my Solution Just before slipping, we say that the block is still at rest, so the net force on the x-axis is: EFx=mg Evaluating, we get: = mg But the frictional force is expressed as the product of coefficient and the normal force so. Us = mg For an inclined plane. The normal force is n=mg Then, Hs=mg cos(e) so tan(e)arrow_forwardIf you push a box across the floor its "physics work" but if you push on the wall it's not. Which of the following choices best explains why? Question 12 options: The direction of the force on the box is not the same direction as the motion. You're applying a force to the box but you are not applying a force to the wall. You're not applying a force to the box but you are applying a force to the wall. The box is moving but the wall is not.arrow_forward30 ft _6 ft- 5 ft B ft The boy pulls on the rope with a force of 80 lb.arrow_forward
- A block weighs 100. N and rests on a horizontal surface. If Ms = 0.50 and uk = 0.20 between the block and the horizontal surface, then (a) What is the magnitude of the frictional force acting on the block? Justify your What is the magnitude of the frictional force acting on the block if a horizontal force of 35.0 N is now used to push the block? Justify your answer with a calculation. What is the magnitude of the minimum horizontally applied force that will start the block sliding? Justify your answer with a calculation. If the magnitude of the applied horizontal force on the block is 55.0 N, what is the magnitude of the frictional force acting on the block? Justify your answer with a calculation.arrow_forwardThis figure shows a person preparing to do a pushup. Calculate the back extensor force (Fm) required to keep the trunk in the static position as shown. Report Fm, in units of N, to 0 decimal points (e.g. 101 N). Report only positive values (i.e. the absolute value). You are allowed an error margin of +/- 10 N from the exact correct answer. The spine and back extensor muscle (Fm) are aligned horizontally with the floor. The ground reaction force (GRF) under the hand is aligned vertically. You only need to consider the weight of the trunk (disregard the head and arms). Here is information you may need to solve this problem: • The GRF is 195 N. • The GRF has a moment arm of 0.4 m relative to the vertebra axis of rotation. • The weight of the trunk is 303 N. • W trunk has a moment arm of 0.29 m relative to the vertebra axis of rotation. • Fm has a moment arm of 0.06 m relative to the vertebra axis of rotation.arrow_forwardSuppose you use an ideal pulley of the type shown in image (a) in the figure below to support a car engine of mass 140 kg. (a) What would be the tension in newtons in the rope? N (b) What force in newtons must the ceiling supply, assuming you pull straight down on the rope? Neglect the pulley system's mass. Narrow_forward
- Which of the following statements are true? Select all correct. Question 4 options: An ideal pulley is frictionless. In a static-pulley system, the net force on individual pulleys may be non-zero. If a rope passes around many ideal pulleys, the tension may be different at either end of the rope. Using pulleys, it is possible to lift a box of weight mg using a tension T < mg If there is more than one rope in a pulley system, then each rope may have a different tension. If a rope passes over an ideal pulley, the tension is larger on one side than the other.arrow_forwardA 1 530-kg automobile has a wheel base (the distance between the axles) of 2.80 m. The automobile's center of mass is on the centerline at a point 1.25 m behind the front axle. Find the force exerted by the ground on each wheel. each front wheel each rear wheel 3.345 X This is the force that acts on a rear wheel. kN You appear to have correctly calculated this force using your incorrect result from part (a). kNarrow_forwardProblem A block of mass m is placed on a rough surface inclined relative to the horizontal. The incline angle is increased until the block start to move. Show that you can obtain the coefficient of static friction Us by measuring the critical angle e where slipping occurs. Solution Just before slipping, we say that the block is still at rest, so the net force on the x-axis is: EFx=mg Evaluating, we get: = mg But the frictional force is expressed as the product of coefficient and the normal force so. = mg For an inclined plane. The nomal force is n=mg Then, Hs=mg cos(e) so: tan(e)arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Principles of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning
Principles of Physics: A Calculus-Based Text
Physics
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
Newton's Second Law of Motion: F = ma; Author: Professor Dave explains;https://www.youtube.com/watch?v=xzA6IBWUEDE;License: Standard YouTube License, CC-BY