COLLEGE PHYSICS
2nd Edition
ISBN: 9781464196393
Author: Freedman
Publisher: MAC HIGHER
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Chapter 4, Problem 41QAP
To determine
The force that is produced with the jaws of life.
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Chapter 4 Solutions
COLLEGE PHYSICS
Ch. 4 - Prob. 1QAPCh. 4 - Prob. 2QAPCh. 4 - Prob. 3QAPCh. 4 - Prob. 4QAPCh. 4 - Prob. 5QAPCh. 4 - Prob. 6QAPCh. 4 - Prob. 7QAPCh. 4 - Prob. 8QAPCh. 4 - Prob. 9QAPCh. 4 - Prob. 10QAP
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- Show that the acceleration of any object down an incline where friction behaves simply (that is, where fk=kN ) is a=g(sinkcos). Note that the acceleration is independent of mass and reduces to the expression found in the previous problem when friction becomes negligibly small (k=0).arrow_forwardA bullet shot from a rifle has mass of 10.0 g and travels to the right at 350 m/s. It strikes a target, a large bag of sand, penetrating it a distance of 34.0 cm. Find the magnitude and direction of the retarding force that slows and stops the bullet.arrow_forwardWhy does an ordinary rifle recoil (kick backward) when fired? The barrel of a recoilless rifle is open at both ends. Describe how Newton's third law applies when one is fired. Can you safely stand close behind one when it is fired?arrow_forward
- Show that the acceleration of any object down a frictionless incline that makes an angle with the horizontal is a=gsin. (Note that this acceleration is independent of mass.)arrow_forwardWhen serving a tennis ball, a player hits the ball when its velocity is zero (at the highest point of a vertical toss). The racquet exerts a force of 540 N on the ball for 5.00 ms, giving it a final velocity of 45.0 m/s. Using these data, find the mass of the ball.arrow_forwardA force acts on a car of mass m so that the speed v of the car increases with position x as v=kx2 where kis constant and all quantities are in SI units. Find the force acting on the car as a function of position.arrow_forward
- A 65-kg person jumps from the first floor window of a burning building and lands almost vertically on the ground with a horizontal velocity of 3 m/s and vertical velocity of -9 m/s. Upon impact with the ground he is brought to rest in a short time. The force experienced by his feet depends on whether he keeps his knees stiff or bends them. Find the force on his feet in each case. a. First find the impulse on the person from the impact on the ground. Calculate both its magnitude and direction. b. Find the average force on the feet if the person keeps his leg stiff and straight and his center of mass drops by only 1 cm vertically and 1 cm horizontally during the impact. c. Find the average force on the feet if the person bends his legs throughout the impact so that his center of mass drops by 50 cm vertically and 5 cm horizontally during the impact. d. Compare the results of part (b) and (c), and draw conclusions about which way is better. You will need to find the time the impact lasts by making reasonable assumptions about the deceleration. Although the force is not constant during the impact, working with constant average force for this problem is acceptable.arrow_forwardRepeat the previous problem for the situation in which the rocket sled decelerates at a rate of 201 m/s2. In this problem, the forces are exerted by the seat and restraining belts.arrow_forwardProfessional Application A car moving at 10 m/s crashes into a tree and stops in 0.26 s. Calculate the force the seat belt exerts on a passenger in the car to bring him to a halt. The mass of the passenger is 70 kg.arrow_forward
- Give an example when a single force cannot replace two forces acting on a body?arrow_forwardIf you need to move a heavy object (e.g. a desk or a dresser), what is easier to do: start it sliding or to keep it sliding? Use evidence from your data and graphs to support your answer.arrow_forward• In a tennis serve, a 0.070-kg ball can be accelerated from rest to36 m>s over a distance of 0.75 m. Find the magnitude of the average force exerted by the racket on the ball during the servearrow_forward
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Newton's Second Law of Motion: F = ma; Author: Professor Dave explains;https://www.youtube.com/watch?v=xzA6IBWUEDE;License: Standard YouTube License, CC-BY