COLLEGE PHYSICS
2nd Edition
ISBN: 9781464196393
Author: Freedman
Publisher: MAC HIGHER
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Chapter 4, Problem 66QAP
To determine
The force between the third and fourth cars compare to the force between the seventh and eighth cars.
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The coefficient of static friction between a persons shoe and the ground is 0.80. Determine the maximum magnitude of acceleration of a 60 kg person, if he starts running on a horizontal surface from rest.
25- A Hospital bed requires a frictional force Fr to keep it moving with constant velocity across a floor. If the coefficient of friction is μ, then the normal force N is given by:
A.μ /Fr
B.μ Fr
C.Fr /μ
D.Fr
E.μ
Only one force acts on an object. Can the object have zero acceleration? Can it have zero velocity? Explain you answer in words.
Chapter 4 Solutions
COLLEGE PHYSICS
Ch. 4 - Prob. 1QAPCh. 4 - Prob. 2QAPCh. 4 - Prob. 3QAPCh. 4 - Prob. 4QAPCh. 4 - Prob. 5QAPCh. 4 - Prob. 6QAPCh. 4 - Prob. 7QAPCh. 4 - Prob. 8QAPCh. 4 - Prob. 9QAPCh. 4 - Prob. 10QAP
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- If a constant, nonzero force is applied to an object, what can you say about the velocity and acceleration of the object?arrow_forwardA 10-lb rock and a 1-lb rock are dropped simultaneously from the same height. (a) Some say that because the 10-lb rock has 10 times as much force acting on it as the 1-lb rock, it should reach the ground first. Do you agree? (b) Describe the situation if the rocks were dropped by an astronaut on the Moon.arrow_forwardCalculate the force a 70.0-kg high jumper must exert on the ground to produce an upward acceleration 4.00 times the acceleration due to gravity. Explicitly show how you follow the steps in the Problem-Solving Strategy for Newton's laws of motion.arrow_forward
- A box rests on the (horizontal) back of a truck. The coefficient of static friction between the box and the surface on which it rests is 0.24. What maximum distance can the truck travel (starting from rest and moving horizontally with constant acceleration) in 3.0 s without having the box slide?arrow_forwardWhen you learn to drive, you discover that you need to up slightly on the brake pedal as you come to a stop or the car will stop with a jerk. Explain this in terms of the relationship between static and friction.arrow_forwardDescribe a situation in which the net external force on a system is not zero, yet its speed remains constant.arrow_forward
- Suppose you are driving a car at a high speed. Why should you avoid slamming on your brakes when you want to stop in the shortest possible distance? (Newer cars have antilock brakes that avoid this problem.)arrow_forwardA 1 000-kg car is pulling a 300-kg trailer. Together, the car and trailer move forward with an acceleration of 2.15 m/s2. Ignore any force of air drag on the car and all frictional forces on the trailer. Determine (a) the net force on the car, (b) the net force on the trailer, (c) the force exerted by the trailer on the car, and (d) the resultant force exerted by the car on the road.arrow_forwardWhat term refers to the tendency of an object to remain at rest or in uniform, straight-line motion? (3.2) (a) mass (b) force (c) inertia (d) external forcearrow_forward
- A man exerts a horizontal force of 112 N on a refrigerator of mass 42.0 kg. If the refrigerator doesnt move, what is the minimum coefficient of static friction between the refrigerator and the floor? (See Section 4.6.)arrow_forwardWhen you learn to drive, you discover that you need to let up slightly on the brake pedal as you come to a stop or the car will stop with a jerk. Explain this in terms of the relationship between static and kinetic friction.arrow_forwardAn object experiences a net zero external unbalanced force. Is it possible for the object to be travelling with a non-zero velocity? If yes,then state an example.arrow_forward
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Newton's Second Law of Motion: F = ma; Author: Professor Dave explains;https://www.youtube.com/watch?v=xzA6IBWUEDE;License: Standard YouTube License, CC-BY