Solid Waste Engineering
3rd Edition
ISBN: 9781305888357
Author: Worrell
Publisher: Cengage
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Question
Chapter 4, Problem 4.3P
To determine
(a)
The shredder which did a better job in reducing the size of the solid waste.
To determine
(b)
The shredder that yielded a more uniform product.
To determine
(c)
The curves for each shredder using Rosin-Rammler plot.
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1. Three samples of aggregates are sieved to obtain the grading curve. A set of different sieves is
stacked with the coarsest mesh at the top. The aggregate is then placed in the top sieve and the
stack is placed in a sieve shaker. The raw data is as follows:
Sieve size (mm)
19
9.5
4.75
2.36
1.18
0.6
0.3
0.15
Pan
Mass of sieve (g)
670
620
620
570
570
520
520
520
490
For each sample:
Plot the grading curve.
a.
b.
Identify the type of gradation.
c. Determine the fineness modulus.
Mass of sieve + aggregates retained (g)
Sample B
mass of the empty measure
mass of measure + water
Sample A
670
770
820
740
720
770
720
570
525
mass of measure + rodded aggregates
mass of measure + loose aggregates
670
1820
620
570
570
670
720
620
544
2. The rodded and loose bulk density of an aggregate sample is to be determined. The following
are acquired during the experiment:
- 12.15 kg
- 27.15 kg
- 34.60 kg
- 25.16 kg
Sample C
670
620
620
670
770
720
620
620
506
From a Fine Aggregate sample, the ff data
are given below to determine only the
SPECIFIC GRAVITIES and ABSORPTION OF
THE SAMPLE.
MASS of oven dried aggregate
428.3g
MASS of PYC filled with water
=652.5g
MASS of aggregate and water
=785.3g
MASS of SSD Aggregate
=459.1g
MASS OF AN EMPTY PYCNOMETER
=125.0g
MASS of oven dried aggregate
428.3g
652.5g
785.3g
459.1g
125.0g
MASS of PYC filled with water
MASS of aggregate and water
MASS of SSD Aggregate
MASS OF AN EMPTY PYCNOMETER
IL || || |I
Referring to the aggregate gradations A, B, and C in Figure , answer the following questions:a. What is the maximum size of each gradation?b. What is the nominal maximum size of each gradation?c. Classify each gradation as dense, open, or gap indicating the reason for each classification.
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- Three aggregates are to be mixed together in the following ratio: Aggregate A 35% Aggregate B 40% Aggregate C 25% For each aggregate, the percent passing a set of five sieves is shown in the following table: Determine the percent passing each sieve for the blended aggregate?arrow_forward4. MECHANICAL SEPARATION A sieve analysis gives the following results: Sieve size (mm) Wt. retained (g) 1.000 0 0.500 64 0.250 0.125 0.063 324 240 48 24 Through 0.063 Plot a cumulative size analysis and a size-distribution analysis, and estimate the weights, per 1000 kg of powder, which would lie in the size ranges 0.150 to 0.200 mm and 0.250 to 0.350 mm.arrow_forwardQuartering (or splitting) means reducing sample sizes into reasonable volumes. Would you expect every after each quartering (or splitting) process, the weight of the original aggregates would be reduced to half or almost half? Why or why not? Defend your reason.arrow_forward
- Coarse aggregate is placed in a rigid bucket and rodded with a tamping rod to determine its unit weight. The following data are obtained: Volume of bucket = 9.3 Liters Mass of empty bucket = 9 kg Mass of bucket filled with dry-rodded coarse aggregate: Trial 1 = 30.25 kg Trial 2 = 29.76 kg Trial 3 = 31.12 kg a. Calculate the individual dry-rodded unit weight for each trial and the average dry-rodded unit weight of all trials. b. If the bulk dry specific gravity of the aggregate is 2.65, calculate the percent voids between aggregates particles for each trial and the average percent voids of all trials.arrow_forwardThree aggregates are to be mixed together in the following ratio:Aggregate A: 35%Aggregate B: 40%Aggregate C: 25%For each aggregate, the percent passing a set of five sieves is shown in Table PDetermine the percent passing each sieve for the blended aggregate.arrow_forwardCoarse aggregate is placed in a rigid bucket and rodded with a tamping rod to determine its unit weight. The following data are obtained: (Note: Write answer with 2 decimal places) Volume of bucket = 1/2 cu.ft Weight of empty bucket = 20.3 Ib Weight of bucket filled with dry rodded coarse aggregate: Trial 1 = 76.6 Ib Trial 2 = 75.1 Ib Trial 3 = 78.8 Ib a. Calculate the average dry-rodded unit weight b. If the bulk dry specific gravity of the aggregate is 2.620, calculate the percent voids between aggregate particles for each trial. {Note: Bulk Dry specific gravity must be multiplied to the unit weight of water to obtain percent voids)arrow_forward
- A sieve analysis test was performed on a sample of aggregate and produced the results shown in Table. Calculate the percent passing through each sieve. What is the maximum size? What is the nominal maximum size? Plot the percent passing versus sieve size on: a. a semilog gradation chart, and b. a 0.45 gradation chart (Figure A.25). Amount Retained, (g) Cumulative Percent Retained SIEVE ΝΟ. SIEVE SIZE Cumulative Amount Percent Passing Retained, (g) 215 885 980 12 2,350 3/8 1,190 4 2,205 8 1,985 10 1,840 40 1.650 100 980 200 660 PAN 60 ΤΟΤAL 15,000arrow_forwardQ1: C: A sieve analysis test was performed on a sample of aggregate and produced the results shown in the Table below, Calculate the percent passing through each sieve. Plot the percent passing versus sieve size. Sieve size, mm Amount Retained, g 25 19 376.7 12.5 888.4 9.5 506.2 4.75 1038.4 2.35 900.1 1.18 891.5 0.6 712.6 0.3 625.2 0.15 581.5 0.075 242.9 Pan 44.9arrow_forward2. A sieve analysis was conducted on an aggregate with a nominal maximum aggregate size of 20 mm. The following data was obtained: Sieve size (mm) Mass retained (g) 37.5 26.5 80 19.0 120 9.5 800 4.75 1450 2.36 130 Pan 80 a) Find the percentage of passing on each sieve and plot the particle size distribution. b) Show the Australian Standard (AS2758) upper and lower limits for this aggregate type on the same plot. As per this standard, is the aggregate well-graded or poorly graded? c) What should we do if the aggregate is poorly graded?arrow_forward
- Coarse aggregate is placed in a rigid bucket and rodded with a tamping rod to determine its unit weight. The following data are obtained: Volume of bucket = 9.3 Liters Mass of empty bucket = 9 kg Mass of bucket filled with dry-rodded coarse aggregate: Trial 1 = 30.25 kg Trial 2 = 29.76 kg Trial 3 = 31.12 kga. Calculate the individual dry-rodded unit weight for each trial and the average dry-rodded unit weight of all trials.b. If the bulk dry specific gravity of the aggregate is 2.65, calculate the percent voids between aggregates particles for each trial and the average percent voids of all trials.arrow_forwardplease show ocmplete solution and figures and sketchesarrow_forwardA sieve analysis test was performed on a sample of aggregate and produced the results shown in Table .Calculate the percent passing through each sieve. Plot the percent passingversus sieve size on:a. a semilog gradation chart, andb. a 0.45 gradation chart (Figure A.25).What is the maximum size? What is the nominal maximum size?arrow_forward
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