EBK PRINCIPLES OF GEOTECHNICAL ENGINEER
9th Edition
ISBN: 8220103611718
Author: SOBHAN
Publisher: CENGAGE L
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Chapter 4, Problem 4.4P
Results from a liquid limit test conducted on a soil are given below.
a. Determine the liquid limit of the soil.
b. If it is known that the PI = 6.5, what would be the plastic limit of the soil?
c. Determine the liquidity index of the soil if win situ = 23.8%
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Laboratory test results for a sample of clay soil for the purpose of evaluating the potential for volume change (swelling, expansion) are as shown. Rate the volume change potential (high, medium, low) for this soil.
LL = 68%
PL = 24%
Particles smaller than 0.002 mm = 45%
The laboratory tests on a soil sample yielded the following results: LL= 54%, PL= 25%, natural moisture content= 29%, the % finer than 0.002 = 18%. Determine the liquidity index of the soil.
a.0.141
b.0.135
c.0.138
d.0.150
The laboratory tests on a soil sample gave the following results:
1). Natural water content, W₁ = 25%
2). Liquid limit, WL = 60%
3). Plastic limit, Wp = 35%
4). Percentage of particle less than 2μ = 20%
The value of activity number is
Chapter 4 Solutions
EBK PRINCIPLES OF GEOTECHNICAL ENGINEER
Ch. 4 - During Atterberg limit tests in the soil mechanics...Ch. 4 - Prob. 4.2PCh. 4 - Prob. 4.3PCh. 4 - Results from a liquid limit test conducted on a...Ch. 4 - The following data were obtained by conducting...Ch. 4 - Refer to the soil in Problem 4.5. Using the...Ch. 4 - Following results are obtained for a liquid limit...Ch. 4 - Prob. 4.8PCh. 4 - Prob. 4.9PCh. 4 - Prob. 4.10P
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- The total volume of a soil specimen is 80,000 mm^3 and has a mass of 152 g. the dry mass of the specimen is 122g, and the density of the soil is 2.65 Mg/m^3. Compute the following index properties: (a) e; (b) n; (c) S; (d) ρt; and (e) ρd. Include phase diagrams.arrow_forwardResults from a liquid limit test conducted on a soil are given below. Number of blows, N 12 19 27 37 Moisture content (%) 35.2 29.5 25.4 21 a. Determine the liquid limit of the soil. b. If it is known that the PI = 6.5, what would be the plastic limit of the soil? C. Determine the liquidity index of the soil if w = 23.8% in situarrow_forwardA SOIL SAMPLE WAS TAKEN FROM A SITE AND WAS PLACED IN A CUBICAL CONTAINER WITH ONE SIDE EQUAL TO 0.1m. THE NET WEIGHT OF THE SOIL IS FOUND OUT TO BE 2kN. AFTER OVEN DRYING, THE WEIGHT WAS REDUCED TO 53%. WHAT IS THE UNIT WEIGHT OF THE SOIL AFTER DRYING? * Your answer A SATURATED SOIL HAS VOID RATIO EQUAL TO 0.65 AND sg = 2.9. WHAT IS THE SUBMERGED UNIT WEIGHT OF THE SOIL? * Your answer THE WEIGHT OF THE VOIDS OF ON SITE SOIL WAS MEASURED AND FOUND OUT TO BE 1 kN. AFTER DRYING, THE WEIGHT OF THE SOLID WAS FOUND TO BE 1 kN. IF THE VOLUME OF THE SOIL IS 0.099 m3, WHAT IS THE NATURAL UNIT WEIGHT OF THE SOIL? * Your answerarrow_forward
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- Permeability tests were performed on a soil sample, under different void ratio and different temperatures and the following results were obtained. Test No. 1 2 Void ratio (e) 0.65 1.02 Temperature °℃ 25° 40⁰ Estimate the coefficient of permeability at a temperature of 20°C for a voids ratio of 0.80. Given the following physical properties of water: At 20°C, n = 10.09 × 10+ and p„ = 0.998 g/cm³ At 25°C, n = 8.95 × 104 g sec/cm² and p k(cm/s) 0.4x10 1.9x10-¹ At 40° C, n = 6.54 × 10-¹ g sec/cm² and p $0.997 g/cm³ = = 0.992 g/cm³arrow_forwardA soil with a volume of 163cm^3 is sampled from a field. It weighs 221g. Then, the sample was saturated until the pores were filled and now weighs 273g. The sample was drained and weighed 236g. The sample then sat out for about 2 weeks until at equilibrium and weighed 206g. After oven drying the sample, it finally weighed 202g. What is the particle density (in g/cm^3) in this soil?arrow_forward2. Given the laboratory results of the Atterberg Limits Test in table below. You may use a chart to determine the liquid limit by plotting the Casagrande graph or you may also use ratio and proportion or calculator in determining the LL. a. Determine the nearest value to the Liquid Limit of the soil. b. Determine the nearest value to the Plastic Limit of the soil. c. Determine the nearest value to the Liquidity Index of the soil. A. Liquid Limit Test Number Cone penetration, mm Weight of Wet Soil +Container, g Weight of Dry Soil +Container, g Weight of Container, g Weight of Water, g Weight of Dry Soil, g Water Content, % B. Plastice Limit and Natural Water Content Test Number Weight of Wet Soil +Container, g Weight of Dry Soil +Container, g Weight of Container, g Weight of Water, g Weight of Dry Soil, g Water Content, % Average, % 1 3 38 20 22.47 21.29 21.27 19.44 18.78 18.75 12.74 13.24 13.2 2 29 Plastic Limit 1 2 23.2 22.8 20.42 20.19 12.9 12.95 4 14 26.12 22.1 13.27 Natural Water…arrow_forward
- 2. In an experiment at the laboratory to determine the water content in a soil sample, the following measurements were made; Weight of soil sample, WT = 0.01 kg Volume of soil sample VT = 0.005 m Volume of soil solids, Vs 0.003 m Weight of water, Ww 0.001 kg Volume of air, Va 0.0008 m Calculate the i. water content in the soil 11. Degree of saturation iii. Void ratio iv. Porosityarrow_forwardA sample of soil in natural state having a volume of 0.00934 m3 weighs 18.11 kg. The sample is allowed to dry in an oven and the weight was reduced to 15.68 kg. The specific gravity of the solid was found to be 2.67. What is the porosity?arrow_forwardPermeability tests were performed on a soil sample, under different void ratio and different temperatures and the following results were obtained. Test No. 1 2 Void ratio Temperature °C (e) 0.65 1.02 25° 40⁰ Estimate the coefficient of permeability at a temperature of 20°C for a voids ratio of 0.80. Given the following physical properties of water: At 20°C, n = 10.09 × 10+ and p„ = 0.998 g/cm³ At 25°C, n = 8.95 × 104 g sec/cm² and p k(cm/s) 0.4x10 1.9x10¹ At 40° C, n = 6.54 × 10 g sec/cm² and p 8 0.997 g/cm³ = 0.992 g/cm³arrow_forward
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