Bundle: Steel Design, Loose-leaf Version, 6th + Mindtap Engineering, 1 Term (6 Months) Printed Access Card
6th Edition
ISBN: 9781337761505
Author: William T. Segui
Publisher: Cengage Learning
expand_more
expand_more
format_list_bulleted
Question
Chapter 4, Problem 4.8.1P
To determine
Maximum Strength
Expert Solution & Answer
Trending nowThis is a popular solution!
Students have asked these similar questions
2. A column HP 14 x 102 of A572 Gr. 55 steel has a length of 15 ft is fixed at both ends. Compute
the design compressive strength for LRFD and the allowable compressive strength for ASD.
(Steel section properties are provided in the next page)
ASTM
Designation
A572
Gr. 42
Gr. 50
Gr. 55
Gr. 60⁰
Gr. 65⁰
Yield
Stress
(ksi)
42
50
55
60
65
Fu
Tensile
Stressa
(ksi)
60
65
70
75
80
The below figure represents a section of a pre-
stressed beam. For a no-tension design where a
is the permissible stress in concrete, the total
moment carrying capacity is
(a)
(c)
d/2
bd²
6
d/2
bd²oc
3
-b-
(b)
(d)
bd² oc
4
bd²a
12
Determine the safe load of the column section shown, if it has a yield strength of 25
MPa. E = 200000 MPa. Use NSCP Specifications. Fyz248 mpa
Properties of Channel Section
d = 305 mm
t₂ = 7.2 mm
A = 3929 mm²
t₁ = 12.7 mm
Ix=53.7 x 10mm¹
x = 117 mm
Properties of W 460 x 74
A = 9450 mm²
b = 190 mm
ly= 1.61 x 10 mm
x = 17.7 mm
tw = 9.0 mm
rx = 188 mm
ry = 41.9 mm
d = 457 mm
tr = 14.5 mm
Ix = 333 x 10 mm
Iy = 16.6 x 10mm*
7.21
When the height of column is 6 m.
When the height of column is 10 m.
Assume K= 1.0
457
CIVIL ENGINEERING-
STEEL DESIGN
Chapter 4 Solutions
Bundle: Steel Design, Loose-leaf Version, 6th + Mindtap Engineering, 1 Term (6 Months) Printed Access Card
Ch. 4 - Prob. 4.3.1PCh. 4 - Prob. 4.3.2PCh. 4 - Prob. 4.3.3PCh. 4 - Prob. 4.3.4PCh. 4 - Prob. 4.3.5PCh. 4 - Prob. 4.3.6PCh. 4 - Prob. 4.3.7PCh. 4 - Prob. 4.3.8PCh. 4 - Prob. 4.4.1PCh. 4 - Prob. 4.4.2P
Ch. 4 - Prob. 4.6.1PCh. 4 - Prob. 4.6.2PCh. 4 - Prob. 4.6.3PCh. 4 - Prob. 4.6.4PCh. 4 - Prob. 4.6.5PCh. 4 - Prob. 4.6.6PCh. 4 - Prob. 4.6.7PCh. 4 - Prob. 4.6.8PCh. 4 - Prob. 4.6.9PCh. 4 - Prob. 4.7.1PCh. 4 - Prob. 4.7.2PCh. 4 - Prob. 4.7.3PCh. 4 - Use A992 steel and select a W14 shape for an...Ch. 4 - Prob. 4.7.5PCh. 4 - Prob. 4.7.6PCh. 4 - Prob. 4.7.7PCh. 4 - The frame shown in Figure P4.7-8 is unbraced, and...Ch. 4 - Prob. 4.7.9PCh. 4 - Prob. 4.7.10PCh. 4 - Prob. 4.7.11PCh. 4 - Prob. 4.7.12PCh. 4 - Prob. 4.7.13PCh. 4 - Prob. 4.7.14PCh. 4 - Prob. 4.8.1PCh. 4 - Prob. 4.8.2PCh. 4 - Prob. 4.8.3PCh. 4 - Prob. 4.8.4PCh. 4 - Prob. 4.9.1PCh. 4 - Prob. 4.9.2PCh. 4 - Prob. 4.9.3PCh. 4 - Prob. 4.9.4PCh. 4 - Prob. 4.9.5PCh. 4 - Prob. 4.9.6PCh. 4 - Prob. 4.9.7PCh. 4 - Prob. 4.9.8PCh. 4 - Prob. 4.9.9PCh. 4 - Prob. 4.9.10PCh. 4 - Prob. 4.9.11PCh. 4 - Prob. 4.9.12P
Knowledge Booster
Similar questions
- A 1.5" x1.5" solid steel bar is made of a steel having an Fy = 50 ksi and an Fu = 65 ksi. It is loaded in tension by the following unfactored forces: • DL = 30 kips ● LL = 50 kips • SL 10 kips = Determine if the bar yields in tension. Assume LRFD. Use the ASCE 7-22 Load Combos and Factors.arrow_forward1. A steel column 10 m long is fabricated from a cover plate and C section arranged as shown. Determine the safe compressive load. Fy = 248 MPa, E= 200 GPa. Use AISC/NSCP Specs. 450 mm -cover plate 'I 12 mm y2 IP d2 10 m C 310 x 37 A = 4720 mm? d = 305 mm bf = 77 mm tf = 12.7 mm tw = 9.8 mm C 310 X 37 a) Both ends of column are fixed b) Both ends of column are hinged c) One end fixed, the other end hinged Use design values of k. tw d=305- Ix = 59.9x10° mm ly = 1.85x10° mm x = 17.1 mm x=17.1arrow_forwardEstimate the cross-sectional area of a 350S125-27 cold-formed shape. a. If the member is tested in tension, what would be the maximum force thesample could carry before reaching the yield strength if the steel has ayield strength of 225 MPa?b. Would you expect a 2.5 m stud to carry the same load in compression?(explain)arrow_forward
- Problem2. The compression member is shown in figure. Find the following: a. The Euler stress Fe. b. The buckling stress Fcr c. The design strength d. The allowable strength e. Does the member satisfactorily meet the design requirements? Why? HSS 8x 8x4 ASTM AS00, Grade B steel (Fy = 46 ksi) 15'arrow_forwardGiven a 4meter both ends fixed W8x21 steel column with Fy = 248MPa. Use ASEP steel manual for section properties. Identify what kind of failure or limit state does the column experience? a. fracture b. yielding c.block shear d.bucklingarrow_forwardTopic: COMBINED STRESS-AXIAL TENSION AND FLEXURE BENDING: STEEL DESIGN Please solve your Solution in a handwritten Note: It should be handwritten pleaseeee Questions A Tension member with no holes is subjected to axial loads of PD=68kN & PL=64kN.It is also subjected with bending moments of MDy=40kN-m & MLy=55kN-m. Is themember adequate? Steel is of A992 Gr 50 Specs. Use LRFD. Neglect the weight of the beam. Section properties:Lp = 1.863 md=459.99mmtw=9.02mmzx= 1835x10^3 mm^4Lr = 5.305 mLb = 4.8 mbf=191.26mmtf=16mmSx=1611x10^3 mm^4 Sy=195x10^3 mm^4Zy=303x 10^3 mm^4 Cb=1.32arrow_forward
- Question #5. Calculate the allowable axial compressive load for a stainless-steel pipe column having an unbraced length of 20 feet. The ends are pin-connected. Use A-11.9 inch, r-3.67 inch and Fy- 40 ksi. Use the appropriate Modulus of Elasticity (E) per material used. All the calculations are needed in submittal. O 212 kip O 202 kip O 196 kip 224 Wiparrow_forwardThe eye bolt, shown in the figure on the right, is used to support the load of 25 kN. The allowable shear stress for the supporting material with the height "h" is 35 MPa. a) Draw the necessary FBD diagrams. b) Choose one of the steel material for the bolt and state its tensile strength and yield strength. 25mm- 25 KNarrow_forwardAnswer the following for the section at Point D Only Calculate the distributed load "w" that: Will cause the section crack Will cause the reinforcement to yield. Material Properties: F'c = 5000 psi Fy = 60000 psi Es = 29000000 psi Ln = 27 ft L wl₂² 16 wl,² 14 CD L wl,2 vl₁² 10 11 win² 16 h: 28 in A=4 in² b=14 in n d: 25 inarrow_forward
- PROBLEM 7. Determine the largest load P that can be applied the plate and bolts. The bolt has a diameter of 12 mm and an allowable shear stress of 80 MPa. Each plate has an allowable tensile stress of 60 MPa, an allowable bearing stress of 70 MPa, and an allowable shear stress of 30 MPa. Answer: P = 25 kips (controls) P/2 P/2 30 mm- 15 mm P 30 mmarrow_forwardFor the column shown what is the nominal compressive strength (Pn) ? Pn=? W12x50 10 12X50 THT X combilevered WIarrow_forward2. The A-36 steel Bar BC had a diameter of 40 mm before the two loads, P, were applied. If after loading, the new diameter of the bar is 39.995 mm, what was P? P -1 m B 0.75 m 1 marrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Steel Design (Activate Learning with these NEW ti...Civil EngineeringISBN:9781337094740Author:Segui, William T.Publisher:Cengage Learning
Steel Design (Activate Learning with these NEW ti...
Civil Engineering
ISBN:9781337094740
Author:Segui, William T.
Publisher:Cengage Learning