Bundle: Steel Design, Loose-leaf Version, 6th + Mindtap Engineering, 1 Term (6 Months) Printed Access Card
6th Edition
ISBN: 9781337761505
Author: William T. Segui
Publisher: Cengage Learning
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Question
Chapter 4, Problem 4.9.4P
To determine
The radius of gyration
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Consider the truss shown in the figure. Determine the force in members ML, MC, and BC and state if these
members are in tension or compression. Show all your work. (lengths AB-BC=CD%3DE%3DEF%3FG=3m)
50 kN 50 kN 50 kN
N
ML K J IH
B CD E F
hod
18 m 6 @3 m
The maximum allowable tensile force in the members of
the truss is (Ft) max = 5.2 kN, and the maximum
allowable compressive force is (Fe) max = 3 kN. Take
d = 2 m. (Figure 1)
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Figure 1
of 1
d
E
d
d/2
C
d/2
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ASSUME THAT THE TRUSS IS SIMPLY SUPPORTED AT JOINTS M AND E.
Determine the stress at member CD if Pu = 18.375 Kips, the area is 23 in?. Answer your problem with the
given unit ksi.
Pu
Pu
Pu
Pu
Pu
Pu
Pu
* (a. 10' - R
it
J I H G F
H (n 10' - KI
K
Ru
8@10'=80'
Chapter 4 Solutions
Bundle: Steel Design, Loose-leaf Version, 6th + Mindtap Engineering, 1 Term (6 Months) Printed Access Card
Ch. 4 - Prob. 4.3.1PCh. 4 - Prob. 4.3.2PCh. 4 - Prob. 4.3.3PCh. 4 - Prob. 4.3.4PCh. 4 - Prob. 4.3.5PCh. 4 - Prob. 4.3.6PCh. 4 - Prob. 4.3.7PCh. 4 - Prob. 4.3.8PCh. 4 - Prob. 4.4.1PCh. 4 - Prob. 4.4.2P
Ch. 4 - Prob. 4.6.1PCh. 4 - Prob. 4.6.2PCh. 4 - Prob. 4.6.3PCh. 4 - Prob. 4.6.4PCh. 4 - Prob. 4.6.5PCh. 4 - Prob. 4.6.6PCh. 4 - Prob. 4.6.7PCh. 4 - Prob. 4.6.8PCh. 4 - Prob. 4.6.9PCh. 4 - Prob. 4.7.1PCh. 4 - Prob. 4.7.2PCh. 4 - Prob. 4.7.3PCh. 4 - Use A992 steel and select a W14 shape for an...Ch. 4 - Prob. 4.7.5PCh. 4 - Prob. 4.7.6PCh. 4 - Prob. 4.7.7PCh. 4 - The frame shown in Figure P4.7-8 is unbraced, and...Ch. 4 - Prob. 4.7.9PCh. 4 - Prob. 4.7.10PCh. 4 - Prob. 4.7.11PCh. 4 - Prob. 4.7.12PCh. 4 - Prob. 4.7.13PCh. 4 - Prob. 4.7.14PCh. 4 - Prob. 4.8.1PCh. 4 - Prob. 4.8.2PCh. 4 - Prob. 4.8.3PCh. 4 - Prob. 4.8.4PCh. 4 - Prob. 4.9.1PCh. 4 - Prob. 4.9.2PCh. 4 - Prob. 4.9.3PCh. 4 - Prob. 4.9.4PCh. 4 - Prob. 4.9.5PCh. 4 - Prob. 4.9.6PCh. 4 - Prob. 4.9.7PCh. 4 - Prob. 4.9.8PCh. 4 - Prob. 4.9.9PCh. 4 - Prob. 4.9.10PCh. 4 - Prob. 4.9.11PCh. 4 - Prob. 4.9.12P
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- Assume that the truss is simply supported at joints M and E. Determine the stress at member FC if Pu = 18.375 Kips, the area is 23 in?. Answer your problem with the given unit ksi. Pu Pu Pu Pu Pu Pu Pu * (a: 10' - J I H * (a 10' - RI K F Rv 8@10'=80arrow_forwardDetermine if the axial stress in nember CF if the area of each member is 75 mm^2. Indicate if T or C.arrow_forwardFrom the beam shown, fc' = 28 MPa, fy = 414 MPa, βh = 1.20, Cc = 40 mm. Take D = 25 mm diameter size. a) Determine the value of maximum spacingarrow_forward
- Determine the thickness of a 2" x 2" angle bar for members BD, BC and DE of truss as shown in the figure. The stresses are not to exceed 20 ksi in tension and 14 ksi in compression. A reduced stress in compression is specified to reduce the danger of buckling. P1 = 4000 lb , P2 = 6000 Ib. Thickness Engineers Edge 4 ft Leg 1 D. 4 It 4 ft -Leg 2arrow_forwardBy internal couple method, what is the maximum stress on the steel side of the transformed section? Consider the beam section shown below. Express your final answer in ksi and use two decimal places. 24" 14 As=3 IN. ² SECTION E (STEEL) = 29 x 10³ K.5.1. E (CONC) = 3.2 x 10³ K.5.1. M = 9 ALLOW. f(STEEL) = 20 K.5.1. ALLOW. f (CONC)= 1.35 K.S.I.arrow_forwardFor the truss and loading shown, determine most economical cross-sectional area (in in2) of member DF, if P = 41894 lb, Q = 37138 Ib, y = 7.73 ft, and the stress in the member is 11.58 ksi . Round off the final answer to two decimal places. 0004(1).png P В D H y C E G 4 panels at 10 ft = 40 ft Add your answerarrow_forward
- Consider the truss shown in (Figure 1). Set P₁ = 8 kN, P₂ = 10 kN, and P3 = 6 kN. Figure E ZA B C 3m P₁ P3 3m < 1 of 1 P₂ -3m- 3m D. ✓ Correct ▼ Part D Determine the force in member BF of the truss and state if this member is in tension or compression. Express your answer to three significant figures and include the appropriate units. Enter negative value in the case of compression and positive value in the case of tension. FBF = 7.67 HA kN Submit Previous Answers Request Answer ? Review * Incorrect; Try Again; 5 attempts remainingarrow_forwardThe truss is made of three A-36 steel members, each having a cross-sectional area of 400 mm². Part A Sc= 0.8 m Submit HÅ Value 0.8 m Determine the magnitude P required to displace the roller to the right 0.3 mm. Express your answer to three significant figures and include appropriate units. Request Answer B 5 kN Units 0.6 m xossal ?arrow_forward1.8-12 A plane truss is subjected to loads 2P and P at joints B and C, respectively, as shown in the figure part a. The truss bars are made of two L102 x 76 x 6.4 steel angles [see Table F-5(b): cross-sectional area of the two angles, A = 2180 mm², figure part b] having an ultimate stress in tension equal to 390 MPa. The angles are con- nected to an 12 mm-thick gusset plate at C (figure part c) with 16-mm diameter rivets; assume each rivet transfers an equal share of the member force to the gusset plate. The ultimate stresses in shear and bearing for the rivet steel are 190 MPa and 550 MPa, respectively. Determine the allowable load Pallow if a safety factor of 2.5 is desired with respect to the ultimate load that can be carried. (Consider tension in the bars, shear in the riv- ets, bearing between the rivets and the bars, and also bear- ing between the rivets and the gusset plate. Disregard friction between the plates and the weight of the truss itself.)arrow_forward
- A truss is loaded as shown in the figure. The cross- sectional area of each member is 500 mm^2. Hint: Use method of section in getting the axial forces. Use the guide cutting sections. L-6 m+6m- N 25 kN 8 m 50 kN - a 8 m 50 kN 8 m 50 kN 8 m B. 9. Find the axial stress in member HK O 35.34 MPa O 31.12 MPa O 33.34 MPa O 37.12 MPa Question 10 10. Find the axial stress in member HJ. O 125 MPa О 123 МPа O 127 MPa O 129 MPaarrow_forwardThe armor shown supports loads of 3 KN. The horizontal elements are 713cm long each. Determine the axial force on element FE; Use the section method to determine the axial force in the FE element and check your result with the nodal or joint method. INFO: Y= 100 cmarrow_forwardSolve this problem using stiffness Method and draw SFD and BMD P=95 STRUCTURE-2arrow_forward
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