Chapter 4, Problem 4P

The volume V and the surface area S of a torus−shaped water tube are given by:

$V=\frac{1}{4}{\pi }^2\left(r_1+r_2\right){\left(r_2-r_1\right)}^2$ and $S={\pi }^2\left(r\frac{2}{2}-r\frac{2}{1}\right)$

If $r_1=0.7r_2$ , determine F and S for $r_2=12$ , 16, 20, 24, and 28 in. Display the results in a four-column table where the first column is r₂, the second r₁, the third V, and the fourth S.