a.
To find: The matrix for the given data.
a.
Answer to Problem 33PPS
The matrix for the given data is
Explanation of Solution
Given information:
The data is given below.
Planet | Distance from Sum | Distance from Earth |
Mercury | 36 | 57 |
Venus | 67.24 | 26 |
Mars | 141.71 | 35 |
Jupiter | 483.88 | 370 |
Saturn | 887.14 | 744 |
Uranus | 1783.98 | 1607 |
Neptune | 2796.46 | 2680 |
Calculation:
The matrix for the data is,
b.
To find: The dimension of the matrix formed.
b.
Answer to Problem 33PPS
The dimension of the matrix formed is
Explanation of Solution
Given information:
The data is given below.
Planet | Distance from Sum | Distance from Earth |
Mercury | 36 | 57 |
Venus | 67.24 | 26 |
Mars | 141.71 | 35 |
Jupiter | 483.88 | 370 |
Saturn | 887.14 | 744 |
Uranus | 1783.98 | 1607 |
Neptune | 2796.46 | 2680 |
Calculation:
The matrix for the data is,
The above matrix has sevenrow and two column.
Thus, the dimension of matrix are
c.
To find: The value of
c.
Answer to Problem 33PPS
The value of
Explanation of Solution
Given information:
The data is given below.
Planet | Distance from Sum | Distance from Earth |
Mercury | 36 | 57 |
Venus | 67.24 | 26 |
Mars | 141.71 | 35 |
Jupiter | 483.88 | 370 |
Saturn | 887.14 | 744 |
Uranus | 1783.98 | 1607 |
Neptune | 2796.46 | 2680 |
Calculation:
The matrix for the data is,
The element
Chapter 4 Solutions
Algebra 2
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