Algebra 2
Algebra 2
1st Edition
ISBN: 9780078884825
Author: McGraw-Hill/Glencoe
Publisher: Glencoe/McGraw-Hill School Pub Co
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Chapter 4.2, Problem 48STP
To determine

To find: The solution for the system of equations.

Expert Solution & Answer
Check Mark

Answer to Problem 48STP

The solution of the system is x=3,y=1,z=4 .

Explanation of Solution

Given:

The given system of equations is,

  2x+3yz=15x+y+4z=308x2y+5z=2

Calculation:

Consider the given inequalities as,

  2x+3yz=15x+y+4z=308x2y+5z=2

Multiply the first equation by 4and secondequation by 4 and then add both the equation as,

  8x+12y4z+5x+y+4z=30413x+13y=26x=2y

Multiply the first equation by 5and add it to the third equation as,

  10x+15y5z8x2y+5z=522x+13y=7

Then, from x=2y ,

  2(2y)+13y=742y+13y=11y=1

Then the value of x=2y is,

  x=2(1)=3

Then consider the equation 29x+26y=98 as,

  29(6y8)+26y=98174232+26y=330y=3320

Consider x=6y8 as,

  x=6(3320)8=1910

Consider the equation 2x+3yz=1 as,

  2(3)+3(1)z=163z=1z=4

Thus, the solution of the system is x=3,y=1,z=4 .

Chapter 4 Solutions

Algebra 2

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