Explanation Given: The point P = ( 0.5 , 1 ) on the curve y 5 + y − 2 x = 1 . Formula used: The formula of linearization L ( x ) , centered at x = a is: L ( x ) = f ′ ( a ) ( x − a ) + f ( a ) Calculation: The curve is y 5 + y − 2 x = 1 . Differentiate the function with respect to x . 5 y 5 − 1 d y d x + d y d x − 2 = 0 5 y 4 d y d x + d y d x − 2 = 0 Simplify the above equation. 5 y 4 d y d x + d y d x − 2 = 0 5 y 4 d y d x + d y d x = 2 ( 5 y 4 + 1 ) d y d x = 2 d y d x = 2 5 y 4 + 1 Now, find the value of d y d x at point P = ( 0.5 , 1 ) . d y d x | P ( 0

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Author: Rogawski

Publisher: MAC HIGHER

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Chapter 4.1, Problem 68E

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Find dydx. Show that the linearization at P. Use L(x) to estimate the y− coordinate of the point on the curve where x=0.55.

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Chapter 4.1, Problem 67E

Chapter 4.1, Problem 69E

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Find d y d x . Show that the linearization at P . Use L ( x ) to estimate the y − coordinate of the point on the curve where x = 0.55 .

Solution Summary: The author explains the formula of linearization L(x), centered at x=a.

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Find dydx. Show that the linearization at P. Use L(x) to estimate the y− coordinate of the point on the curve where x=0.55.

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Chapter 4 Solutions