a. Explanation Given information: A function is given as, f ( x ) = 2 x 2 − 8 x + 7 . Concept used: Critical Point: a number c in the domain of f is called a critical point if either f ' ( c ) = 0 or f ' ( c ) does not exists. Calculation: Given function is, f ( x ) = 2 x 2 − 8 x + 7 . Using power rule, d d x ( x n ) = n x n − 1 So, f ' ( x ) = 2 ( 2 x ) − 8 ( 1 ) + 0 ⇒ f ' ( x ) = 4 x − 8 To find critical points put f ' ( x ) = 0 b. To determine The extreme values of f in the given interval of [ 0 , 5 ] . c. To determine The extreme values of f in the given interval of [ − 4 , 1 ] .

4th Edition

ISBN: 9781319323394

Author: Rogawski

Publisher: MAC HIGHER

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Question

Chapter 4.2, Problem 17E

To determine

All critical points x=c of given function and function value at critical points , f(c) .

To determine

The extreme values of f in the given interval of [0,5] .

To determine

The extreme values of f in the given interval of [−4,1] .

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Chapter 4.2, Problem 16E

Chapter 4.2, Problem 18E

Chapter 4 Solutions

CALCULUS W/SAPLING ACCESS >IC<

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All critical points x = c of given function and function value at critical points , f ( c ) .

Solution Summary: The author explains that a number c in the domain of f is called the critical point if either F'(c)=0 or

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All critical points x=c of given function and function value at critical points , f(c) .

The extreme values of f in the given interval of [0,5] .

The extreme values of f in the given interval of [−4,1] .

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Chapter 4 Solutions