ORGANIC CHEMISTRY 2-SEMESTER-ACCESS
4th Edition
ISBN: 9781119659532
Author: Klein
Publisher: WILEY
expand_more
expand_more
format_list_bulleted
Question
Chapter 4.2, Problem 3ATS
Interpretation Introduction
Interpretation:
The bond line structure and isomers of hexane should be drawn. The parent chain for each isomer should be identified.
Concept Introduction:
Compounds consisting of carbon and hydrogen are known as hydrocarbons. Hydrocarbons are classified as a saturated hydrocarbon and unsaturated hydrocarbon. Saturated hydrocarbons are those hydrocarbons in which a carbon-carbon single bond is present as carbon is linked with four atoms.
Saturated hydrocarbon is known as
Expert Solution & Answer
![Check Mark](/static/check-mark.png)
Want to see the full answer?
Check out a sample textbook solution![Blurred answer](/static/blurred-answer.jpg)
Students have asked these similar questions
4. Octatetraene, C8H10, is an 8-membered linear carbon chain with alternating single and double bonds. As a result, each carbon is left with an unhybridized p-orbital containing one electron. This problem will take you through steps to construct and fill the molecular orbital diagram for octatetraene based on the way these different p-orbitals can come together. a) The various molecular orbitals formed from octatetraene’s 8 unhybridized p-orbitals are shown on the next page. Draw the nodal planes for each molecular orbital. Hint: A nodal plane is a line through the molecule that denotes the sites of destructive interference. An example is shown below with ethylene. b) Based on the nodal planes, arrange the energy levels corresponding to the 8 molecular orbitals on the energy level diagram (label them using the numbering provided on the left side of the molecular orbitals) on the next page, in order of lowest to highest energy. c) Populate your molecular…
Explain how covalent bonds are formed in each of the following compounds in terms of
orbital hybridisation and overlap of orbitals
(i) Ethene, C2H4
(ii) Ethyne, C2H2
2. Account for the bond angle differences between (i) H-C-H (109.5°) in methane
and H-S-H (90°); H-C-H (109.5°) and H-O-H (107.5°) in water
The H-S-H has two lone pairs; The H-O-H has two lone pairs
The H-S-H has no hybridization at p-orbitals; The H-O-H has two lone pairs
The H-S-H has two lone pairs; The H-O-H has no hybridization at p-orbitals
The H-S-H has no hybridization at p-orbitals; The H-O-H has no hybridization at p-
orbitals
Chapter 4 Solutions
ORGANIC CHEMISTRY 2-SEMESTER-ACCESS
Ch. 4.2 - Prob. 1LTSCh. 4.2 - Prob. 1PTSCh. 4.2 - Prob. 2PTSCh. 4.2 - Prob. 3ATSCh. 4.2 - Prob. 2LTSCh. 4.2 - Prob. 4PTSCh. 4.2 - Prob. 5ATSCh. 4.2 - Prob. 3LTSCh. 4.2 - Prob. 6PTSCh. 4.2 - Prob. 7ATS
Ch. 4.2 - Prob. 4LTSCh. 4.2 - Prob. 8PTSCh. 4.2 - Prob. 9PTSCh. 4.2 - Prob. 10ATSCh. 4.2 - Prob. 5LTSCh. 4.3 - Prob. 6LTSCh. 4.3 - Prob. 14PTSCh. 4.6 - Prob. 7LTSCh. 4.6 - Prob. 16PTSCh. 4.8 - Prob. 8LTSCh. 4.12 - Prob. 11LTSCh. 4.12 - Prob. 25PTSCh. 4.14 - Prob. 33CCCh. 4.14 - Prob. 34CCCh. 4.14 - Prob. 35CCCh. 4 - Prob. 36PPCh. 4 - Prob. 51PPCh. 4 - Prob. 52PPCh. 4 - Prob. 53PPCh. 4 - Prob. 54PPCh. 4 - Prob. 55PPCh. 4 - Prob. 56PPCh. 4 - Prob. 57PPCh. 4 - Prob. 58PPCh. 4 - Prob. 59PPCh. 4 - Prob. 69ACPCh. 4 - Prob. 73IPCh. 4 - Prob. 76IP
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.Similar questions
- Draw the structure of the two tertiary (3°) amines with molecular formula C6H15N that contain a group with 3 carbon atoms in the largest group. You do not have to consider stereochemistry. You do not have to explicitly draw H atoms.arrow_forwardSketch the ultraviolet absorption spectrum of 1,3-Butadiene, matching peaks to electronic transitions. show that four isolated p orbital on carbon atoms combine to form pi orbitalarrow_forwardPyrazine, C4H4N2, is used in the synthesis of vitamins and drugs. The molecule can be thought of replacing two -CH units in benzene with a nitrogen atom in each of the 1,4- positions. pyrazine Describe the o and a bonding in pyrazine by analyzing the hybridization state, valence electron count and o-framework. How many delocalized electrons are present? Explain your answer. How many bonding and anti-bonding 7-type molecular orbitals are present? Explain your answer. Draw the detailed MO diagram of the 7-system. Explain your answer.arrow_forward
- 7 The pentadienyl radical, H2C“CH¬CH“CH¬CH2#, has its unpaired electron delocalized over three carbon atoms.(a) Use resonance forms to show which three carbon atoms bear the unpaired electron.arrow_forwardThere are three different dichloroethylenes (molecular for-mula C₂H₂Cl₂), which we can designate X, Y, and Z. CompoundX has no dipole moment, but compound Z does. Compounds Xand Z each combine with hydrogen to give the same product:C₂H₂Cl₂ (X or Z) +H₂→ClCH2-CH2Cl What are the structures of X, Y, and Z? Would you expect com-pound Y to have a dipole momenarrow_forwardAn acyclic molecule has the molecular formula C8H14. How many pi bonds does it contain?arrow_forward
- Section 7.3 shows that the compound 2-butene exists intwo isomeric forms, which can be interconverted only bybreaking a bond (in that case, the central double bond).How many possible isomers correspond to each of the following chemical formulas? Remember that a simple rotation of an entire molecule does not give a different isomer.Each molecule contains a central CuC bond.(a) C2H2Br2(b) C2H2BrCl(c) C2HBrClFarrow_forwardDraw the bond-line structure of the compound (1R)-1-chloro-1-cyclohexylpropan-1-olarrow_forwardThe pentadienyl radical, H2C“CH¬CH“CH¬CH2#, has its unpaired electron delocalized over three carbon atoms.(a) Use resonance forms to show which three carbon atoms bear the unpaired electron.(b) How many MOs are there in the molecular orbital picture of the pentadienyl radical?arrow_forward
- Write a bond line structural formula for the following molecules: a) H2C=C(CH3)C=CC(CH3)3 b) (CH3CH2)½CHCH2OCH3 c) CH3CH=CHCH(OH)CH3 (draw the double bond in a cis conformation)arrow_forwardWhich of the following arrangements of p atomic orbitals gives the highest energy p-bonding molecular orbital of 1,3- butadiene?arrow_forwardIf we extend the formation of the four pi-molecular orbitals to forming pi-molecular orbitals by the combination of the six un-hybridized p-orbitals in 1,3,5-hexatriene? Among those pi- molecular orbitals for 1,3,5-hexatriene, how many electrons are in the lowest-enery pi- molecular orbital? 1,3,5-hexatrienearrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Chemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage LearningChemistry: Principles and PracticeChemistryISBN:9780534420123Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward MercerPublisher:Cengage Learning
![Text book image](https://www.bartleby.com/isbn_cover_images/9781285199047/9781285199047_smallCoverImage.gif)
Chemistry: The Molecular Science
Chemistry
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:Cengage Learning
![Text book image](https://www.bartleby.com/isbn_cover_images/9780534420123/9780534420123_smallCoverImage.gif)
Chemistry: Principles and Practice
Chemistry
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Cengage Learning
Group Theory - Learn like Expert with 3D animation | Introduction for Beginners | ONE Chemistry; Author: One Chemistry;https://www.youtube.com/watch?v=Lz2ih8fkgDs;License: Standard YouTube License, CC-BY