Explanation Given information: The given function is y = x 2 3 − x 2 . Concept used: Critical Points: to find the critical points of any function follows the steps below, Step 1: find the first derivative of the function. Step 2: equate the first derivative to zero and find the value of the variables. Consider the given function. y = x 2 3 − x 2 Differentiate the function with respect to x . y ′ = 2 3 x 2 3 − 1 − 2 x 2 − 1 = 2 3 x − 1 3 − 2 x Equate the derivative to zero y ′ = 0 to find the value of x . 2 3 x − 1 3 − 2 x = 0 x ( 2 3 x − 1 3 − 1 − 2 ) = 0 x ( 2 3 x − 4 3 − 2 ) = 0 If x = 0 then first point is x = 0

4th Edition

ISBN: 9781319050733

Author: Rogawski

Publisher: MAC HIGHER

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Chapter 4.3, Problem 50E

To determine

To find: the critical points, maxima, and minima points of the function.

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Chapter 4.3, Problem 49E

Chapter 4.3, Problem 51E

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Chapter 4 Solutions

CALCULUS (CLOTH)

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the critical points, maxima , and minima points of the function.

Solution Summary: The author explains how to find the critical points, maxima, and minima points of a function.

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Chapter 4 Solutions