Explanation Place the segment in the x y − plane with A at the origin and B (10, 0) Let x be the distance from A then 10 − x is the distance from B the total amount of light is f ( x ) = 1 A x 2 + I B ( 10 − x ) 2 = I A ( 1 x 2 + 4 ( 10 − x ) 2 ) f ' ( x ) = I A ( 8 ( 10 − x ) − 2 x 3 ) = 0 For 0 ≤ x ≤ 10 4 =

4th Edition

ISBN: 9781319050733

Author: Rogawski

Publisher: MAC HIGHER

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Question

Chapter 4.6, Problem 36E

To determine

The amount of light reaching a point at a distance r from a light source A of intensity IA is IA/r2 suppose that a second light source light source B of intensity IB=4IA is located 10 m from A find the point on the segment joining A and B where the total amount of light is at minimum

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Chapter 4.6, Problem 35E

Chapter 4.6, Problem 37E

Chapter 4 Solutions

CALCULUS (CLOTH)

Ch. 4.1 - Prob. 1PQ Ch. 4.1 - Prob. 2PQ Ch. 4.1 - Prob. 3PQ Ch. 4.1 - Prob. 4PQ Ch. 4.1 - Prob. 1E Ch. 4.1 - Prob. 2E Ch. 4.1 - Prob. 3E Ch. 4.1 - Prob. 4E Ch. 4.1 - Prob. 5E Ch. 4.1 - Prob. 6E

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The amount of light reaching a point at a distance r from a light source A of intensity I A is I A / r 2 suppose that a second light source light source B of intensity I B = 4 I A is located 10 m from A find the point on the segment joining A and B where the total amount of light is at minimum

Solution Summary: The author explains how to determine the amount of light reaching the point at a distance r from the light source A at the origin and B.

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The amount of light reaching a point at a distance r from a light source A of intensity IA is IA/r2 suppose that a second light source light source B of intensity IB=4IA is located 10 m from A find the point on the segment joining A and B where the total amount of light is at minimum

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Chapter 4 Solutions