The proof of K 1 = 1 2 m c 2 [ ( m c 2 − m 1 c 2 ) 2 − ( m 2 c 2 ) 2 ] .

Question

Want to see the full answer?

Answer 1

Question

Chapter 43, Problem 66GP

To determine

The proof of K1=12mc2[(mc2−m1c2)2−(m2c2)2].

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

1. You and your lab partner are making measurements on particle decay in the lab. You make the following measurements on particle A: m₁ = 498 MeV/c² and ₁ = 0.462c î. You observe VA particle A decay to particles B and C. Your lab partner makes the following measurements: MB = mc = = 140 MeV/c² and ✓ = −0.591c î. (a) Calculate the total energy for each particle. (b) Find the velocity (magnitude and direction) of particle C. (c) Spock is in a ship moving with VB a velocity of vs = 0.635c î observing the same particle decay. What values does he measure for the velocities of particle B and particle C?

a) A K° meson (mass 497.61 MeV/c2) decays to a t, T pair with a mean lifetime of 0.89 x 10-10 s. Suppose the K° has a kinetic energy of 276 MeV when it decays, and that the two A mesons emerge at equal angles to the original K° direction. Calculate the kinetic energy of each T meson and the opening angle between them. The mass of a 7 meson is 139.57 MeV/c2.

06 (a) A stationary particle 1 decays into particles 2 and 3, which move off with equal but oppositely directed momenta. Show that the kinetic energy K2 of particle 2 is given by K, -[(E, - E) – E, 2E, where E1, E2, and Ez are the rest energies of the particles. (b) A stationary positive pion + (rest energy 139.6 MeV) can de- cay to an antimuon ut (rest energy 105.7 MeV) and a neutrino v (rest energy approximately 0). What is the resulting kinetic energy of the antimuon?