Bundle: Understanding Motor Controls, 4th + Mindtap Electrical, 2 Terms (12 Months) Printed Access Card
4th Edition
ISBN: 9780357097755
Author: Stephen L. Herman
Publisher: Cengage Learning
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Chapter 43, Problem 8RQ
Refer to Figure 43–6 and assume the motor is to rotate in the opposite direction. How can the belt slack be maintained on top?
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Q. No 1.
Derive the expressions for A, B, & C in the given figure with the help of clear
drawing and stepwise procedure. Also find the expression for the Length of the belt drives
for open and closed belt drives.
B=?.
sin D+d
2C
A=?
sin D+d
2C
VAC - (D+ dỷ
An Electrical motor (heavy start) that delivers 53,57 kW at 1440 r/min must be connected to a
rotary compressor with a wedge belt drive. The compressor must operate 24 hours per day with
a shaft speed of approximately 966 r/min. The center distance must be closest to 1000 mm.
For the belt drive shown below calculate the contact angle 0, if:
D = 100 mm;
d = 30 mm;
C = 300 mm.
Chapter 43 Solutions
Bundle: Understanding Motor Controls, 4th + Mindtap Electrical, 2 Terms (12 Months) Printed Access Card
Ch. 43 - What are the disadvantages of low-speed, directly...Ch. 43 - Prob. 2RQCh. 43 - What three alignment checks should be made to...Ch. 43 - Prob. 4RQCh. 43 - Induction motors should not be used below a...Ch. 43 - What is the primary reason for using a pulley...Ch. 43 - How tightly should V-belts be adjusted?Ch. 43 - Refer to Figure 436 and assume the motor is to...Ch. 43 - A machine delivered for installation has a 2-inch...
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- a 7460 w split-phase motor running at 1750 rpm is used to drive a rotary pump. the pump should run continuously at approximately 1175 rpm. the center distance should not exceed 1118 mm. space limits the diameter of the driven pulley to 292 mm. design a. the pulley diameters, b. the belt size, and c. the number of belt required.arrow_forwardAn industrial fan running at 600 rpm is driven by a 25 kW, 960 rpm, induction motor. The pulley mounted on the motor shaft is 270 mm. Center to center distance is 1.45 m and use f = 0.35. Determine the length of leather beltarrow_forwardTO THE NEXT PROBLEM Design a complete belt drive system for an AC motor (NT) running a fan 12 hrs/day, with an input power 10 hp and input speed of 1000 RPM. The desired output RPM and center distances are 500 RPM and 36 inch, respectivelyarrow_forward
- Derive the expressions for A, B, & C in the given figure with the help of clear drawing and stepwise procedure. Also find the expression for the Length of the belt drives for open and closed belt drives.arrow_forwardA 7460 W split-phase motor running at 1750 rpm is used to drive a rotary pump. The pump should run continuously at approximately 1175 rpm. The center distance should not exceed 1118 mm. Space limits the diameter of the driven pulley to 292 mm. Determine: a. the pulley diameters, b. the belt size, and c. the number of belt required.arrow_forwardQ5: What kinds of Belt drives with explanation only. onearrow_forward
- An AC motor operating at 870 rpm drives a sheave for a 5V belt with a diameter of 8.9 inches. The desired output shaft speed is 560 rpm. a. For the output shaft, is the 13.1 inch sheave, or the 13.9 inch sheave, a better choice?arrow_forward... An open belt drive operates under the following condition: driving pulley of 84 in. in diameter, driven pulley of 48 in. in diameter, and speed of driving pulley 150 rpm. Which of the following is the velocity of the belt?Group of answer choices 2640 ft/min 5280 ft/min 3300 ft/min 4620 ft/minarrow_forwardA hammer mill is driven by a High Torque (HT) AC motor. The system is used for 8 hours /day. Input speed is 870 RPM and input power is 25 HP. Nominal output speed is 310 RPM. Design a V-belt drive and specify:(a) (b) (c) (d) (e)the belt size,the sheave sizes,the number of belts, theactualoutputspeed,the center distance. Show all your calculations.arrow_forward
- What is the primary reason for using a pulley drive?arrow_forwardWhat type, size, and a number of classical V-belts is recommended for this system. The motor is rated at 3 Hp, VFD controlled and runs at 1750 rpm under load. The output speed required is 1075 rpm. The application is a saw that cuts wood and the environment is dusty. Target center distance is 18 inches, but 16 to 20 inches is acceptable. Due to clearance constraints, the driven pulley may not be larger than 6 ½ in. The motor will slide to adjust tension.8 hours service per day.arrow_forwardThe figure below shows an electromechanics system that is consist of a DC motor controlled by a servo amplifier, and lead screw via a worm gear. The lead screw extends and contracts to drive a mass. DC Motor Worm Gear and Lead Screw Motor Servoamplifierarrow_forward
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