Physics for Scientists and Engineers with Modern, Revised Hybrid (with Enhanced WebAssign Printed Access Card for Physics, Multi-Term Courses)
9th Edition
ISBN: 9781305266292
Author: Raymond A. Serway, John W. Jewett
Publisher: Cengage Learning
expand_more
expand_more
format_list_bulleted
Question
Chapter 45, Problem 15P
To determine
The Coulomb barrier or electric potential energy.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
Alpha particles are projected toward a gold foil from a distance that is sufficiently large to consider the Coulomb force negligible. The gold nuclei have 118 neutrons and 79 protons. If a 3.60 MeV alpha particle has a scattering angle of 180° and the gold nucleus does not recoil, determine the distance of closest approach of the alpha particle.
Calculate the distance of closest approach for a head-on collision between a 5.30 MeV alpha particle and a copper nucleus.
An alpha particle with kinetic energy 11.0 Me V
makes a collision with lead nucleus, but it is not
"aimed" at the center of the lead nucleus, and has
an initial nonzero angular momentum (with respect
to the stationary lead nucleus) of magnitude
L%=pob, where po is the magnitude of the initial
momentum of the alpha particle and
b=1.50x10-12m (Assume that the lead nucleus
remains stationary and that it may be treated as a
point charge. The atomic number of lead is 82. The
alpha particle is a helium nucleus, with atomic
number 2.)
Repeat for b=1. 10×10-13 m.
Express your answer in meters.
ΑΣφ
Submit
Request Answer
Part C
Repeat for b=1.50×10-14 m.
Express your answer in meters.
Chapter 45 Solutions
Physics for Scientists and Engineers with Modern, Revised Hybrid (with Enhanced WebAssign Printed Access Card for Physics, Multi-Term Courses)
Ch. 45.1 - When a nucleus undergoes fission, the two daughter...Ch. 45.2 - Prob. 45.2QQCh. 45.3 - Prob. 45.3QQCh. 45.4 - Prob. 45.4QQCh. 45 - Prob. 1OQCh. 45 - Prob. 2OQCh. 45 - Prob. 3OQCh. 45 - Prob. 4OQCh. 45 - Prob. 5OQCh. 45 - Prob. 6OQ
Ch. 45 - Prob. 7OQCh. 45 - Prob. 8OQCh. 45 - Prob. 9OQCh. 45 - Prob. 1CQCh. 45 - Prob. 2CQCh. 45 - Prob. 3CQCh. 45 - Prob. 4CQCh. 45 - Prob. 5CQCh. 45 - Prob. 6CQCh. 45 - Prob. 7CQCh. 45 - Prob. 8CQCh. 45 - Prob. 1PCh. 45 - Prob. 2PCh. 45 - Prob. 3PCh. 45 - Prob. 4PCh. 45 - Prob. 5PCh. 45 - Prob. 6PCh. 45 - Prob. 7PCh. 45 - Prob. 8PCh. 45 - Prob. 9PCh. 45 - Prob. 10PCh. 45 - Prob. 11PCh. 45 - Prob. 12PCh. 45 - Prob. 13PCh. 45 - Prob. 14PCh. 45 - Prob. 15PCh. 45 - Prob. 16PCh. 45 - Prob. 18PCh. 45 - Prob. 19PCh. 45 - Prob. 20PCh. 45 - Prob. 21PCh. 45 - Prob. 22PCh. 45 - Prob. 23PCh. 45 - Prob. 24PCh. 45 - Prob. 25PCh. 45 - Prob. 26PCh. 45 - Prob. 27PCh. 45 - Prob. 28PCh. 45 - Prob. 29PCh. 45 - Prob. 30PCh. 45 - Prob. 31PCh. 45 - Prob. 32PCh. 45 - Prob. 33PCh. 45 - Prob. 34PCh. 45 - Prob. 35PCh. 45 - Prob. 36PCh. 45 - Prob. 37PCh. 45 - Prob. 41PCh. 45 - Prob. 42PCh. 45 - Prob. 43PCh. 45 - Prob. 44PCh. 45 - Prob. 45PCh. 45 - Prob. 46APCh. 45 - Prob. 47APCh. 45 - Prob. 48APCh. 45 - Prob. 49APCh. 45 - Prob. 51APCh. 45 - Prob. 52APCh. 45 - Prob. 53APCh. 45 - Prob. 54APCh. 45 - Prob. 55APCh. 45 - Prob. 56APCh. 45 - Prob. 57APCh. 45 - Prob. 58APCh. 45 - Prob. 59APCh. 45 - Prob. 60APCh. 45 - Prob. 61APCh. 45 - Prob. 62APCh. 45 - Prob. 63APCh. 45 - Prob. 64APCh. 45 - Prob. 65APCh. 45 - Prob. 66APCh. 45 - Prob. 67APCh. 45 - Prob. 68APCh. 45 - Prob. 69APCh. 45 - Prob. 70APCh. 45 - Prob. 71APCh. 45 - Prob. 72APCh. 45 - Prob. 73AP
Knowledge Booster
Similar questions
- In a Rutherford scattering experiment, assume that an incident alpha particle (radius 1.80 fm) is headed directly toward a target gold nucleus (radius 6.23 fm).What energy must the alpha particle have to just barely “touch” the gold nucleus?arrow_forwardIn a Rutherford scattering experiment, an a - particle (charge = 12e) heads directly toward a gold nucleus (charge = +79e). The alpha - particle had a kinetic energy of 5.0 MeV when very far (r -> infinity`) from the nucleus. Assuming the gold nucleus to be fixed in space, determine the distance of closest approach. Hint: Use conservation of energy with PE = ke q1q2/r.arrow_forwardAlpha particles of kinetic energy K are scattered either from a gold foil or a silver foil of identical thickness. What is the ratio of the number of particles scattered at angles greater than 90° by the gold foil to the same number for the silver foil?arrow_forward
- A certain medium has the following properties: Σs = 0.1 cm−1,Σa = 0.01 cm−1. a) What is the probability that a neutron will travel 1 cm in this medium without interacting with a nucleus? b) If the neutron speed is 2 ×105 cm s−1, what is the average time between scattering collisions?arrow_forwardThe isotope of Nickel, 66Ni decays by β emission, has a half-life of 2.3 days. and the β particles have an average energy of 65 keV. A source consisting of this isotope has an initial number of atoms N0 = 5 x 1020 atoms. What is the power per unit area initially deposited by this source in a small target placed at 1m distance from the source? Select one: a. 35 W/m2 b. 7.6 MW/m2 c. 1.45 W/m2 d. 4.5 kW/m2arrow_forwardAlpha particles of kinetic energy 6.9M V are incident at a rate of 3.1x 10" per second on a copper foil of thickness 3.1 x 10-m. A circular detector of diameter 1.0cm is placed 13cm from the foil at an angle of 30° with the direction of the incident alpha particles. At what rate does the detector measure scattered alpha particles? (The molar mass of copper is 63.5 and its density is 8.9em-)arrow_forward
- For the Rutherford (Geiger and Marsden) experiment with 5.5 MeV alpha particles on a 1 um gold foil, and for the six angles (decades) between 10-5 and 10° rad, calculate the Rutherford differential cross section (DCS), dor/d2, (a) without and (b) with screening. Represent both results graphically and draw conclusions.arrow_forwardA physicist has developed a device that generates a beam of alpha particles each of which is a helium nucleus, consisting of two protons, two neutrons, and no electrons. The device ejects a steady stream of 2360 alpha particles per second. In order to test different shielding materials for a test chamber that will house the alpha particle generator, prepare a sheet of one potential material in an clectrically neutral state, mount it on a perfectly insulating stand, and fire the alpha particle device at it for 37.3 seconds. Afterward, the charge of the sheet is 5.46 x 10-15 C. Assume that none of the alpha particles bounced back from the sheet, meaning that the alpha particles were either captured by the shielding or penetrated completely through the shielding. What percentage of the alpha particles penetrated completely through the shielding material?arrow_forwardIn an experiment, it was observed that a backward scattered ( an angle greater or equal to 90 degrees) alpha particles formed a beam that was energetic and was directed at a piece of gold foil as thin as 6.0 * 10^-7m. Assuming that an alpha particle scatters from the foil, what is the maximum scattering angle?arrow_forward
- Alpha particles of energy 8.4 MeV are incident on a silver foil of thickness 6.5 x 10-6 m. For a certain value of the impact parameter, the alpha particles lose exactly half their incident kinetic energy when they reach their minimum separation from the nucleus. Find the minimum separation, the impact parameter, and the scattering angle.arrow_forwardWhen an alpha particle collides elastically with a nucleus, the nucleus recoils. Suppose a 6.00 MeV alpha particle has a head-on elastic collision with a silver-108 nucleus that is initially at rest. (a) What is the kinetic energy of the recoiling nucleus? MeV (b) What is the kinetic energy of the rebounding alpha particle? MeVarrow_forwardIn a Rutherford scattering experiment, alpha particles having kinetic energy of 7.70 MeV are fired toward a gold nucleus that remains at rest during the collision. The alpha particles come as close as 29.5 fm to the gold nucleus before turning around. (a) Calculate the de Broglie wavelength for the 7.70-MeV alpha particle and compare it with the distance of closest approach, 29.5 fm. (b) Based on this comparison, why is it proper to treat the alpha particle as a particle and not as a wave in the Rutherford scattering experiment?arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Modern PhysicsPhysicsISBN:9781111794378Author:Raymond A. Serway, Clement J. Moses, Curt A. MoyerPublisher:Cengage Learning
Modern Physics
Physics
ISBN:9781111794378
Author:Raymond A. Serway, Clement J. Moses, Curt A. Moyer
Publisher:Cengage Learning