Concept explainers
To find: An integral upper bound using Upper Bound Theorem and to find an integral lower bound of the zeros using Lower Bound Theorem, of
Answer to Problem 28E
Upper bound: 6
Lower bound:
Explanation of Solution
Given information:
Calculation:
r | 1 - 6 2 3 - 5 | |
1 | 1 - 5 - 3 0 | - 5 |
5 | 1 - 1 - 3 -12 | - 65 |
6 | 1 0 2 15 | 85 |
Since
r | 1 6 2 - 3 - 5 | |
1 | 1 7 9 6 | 1 |
Since 1 is the upper bound of
Then − 1 is the lower bound of
Upper bound: 6
Lower bound:
Chapter 4 Solutions
Advanced Mathematical Concepts: Precalculus with Applications, Student Edition
Additional Math Textbook Solutions
Thomas' Calculus: Early Transcendentals (14th Edition)
Calculus and Its Applications (11th Edition)
Calculus: Early Transcendentals (2nd Edition)
University Calculus: Early Transcendentals (4th Edition)
Precalculus (10th Edition)
Single Variable Calculus: Early Transcendentals (2nd Edition) - Standalone book
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- Calculus: Early TranscendentalsCalculusISBN:9781319050740Author:Jon Rogawski, Colin Adams, Robert FranzosaPublisher:W. H. FreemanCalculus: Early Transcendental FunctionsCalculusISBN:9781337552516Author:Ron Larson, Bruce H. EdwardsPublisher:Cengage Learning