(a) Answer The graph Explanation Given information: Music: The frequency of a sound wave is called its pitch. The pitch p of a musical tone and its wavelength w are related by the equation p = v w , where v is the velocity of sound through air. Suppose a sound wave has a velocity of 1056 feet per second. Calculation: p = 1056 2 (b) To determine What lines are close to the maximum values for the pitch and the wavelength? Answer Both axis are close Explanation Given information: Music: The frequency of a sound wave is called its pitch. The pitch p of a musical tone and its wavelength w are related by the equation p = v w , where v is the velocity of sound through air. Suppose a sound wave has a velocity of 1056 feet per second. Calculation: Both axis are close (c) To determine What happens to the pitch of the tone as the wavelength decreases? Answer As the wavelength decreases the pitch increases Explanation Given information: Music: The frequency of a sound wave is called its pitch. The pitch p of a musical tone and its wavelength w are related by the equation p = v w , where v is the velocity of sound through air. Suppose a sound wave has a velocity of 1056 feet per second. Calculation: The graph represents an inverse variation. As one value increases the other decreases and As the wavelength decreases the pitch increases. (d) To determine What happens to the pitch of the tone if the wavelength is doubled? Answer If we double the wavelength then the pitch is halved Explanation Given information: Music: The frequency of a sound wave is called its pitch. The pitch p of a musical tone and its wavelength w are related by the equation p = v w , where v is the velocity of sound through air. Suppose a sound wave has a velocity of 1056 feet per second. Calculation: The opposite reaction If you double the wavelength, Then the pitch is halved.

Advanced Mathematical Concepts: Precalculus with Applications, Student Edition

1st Edition

ISBN: 9780078682278

Author: McGraw-Hill, Berchie Holliday

Publisher: Glencoe/McGraw-Hill

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Videos

Question

Chapter 4.7, Problem 46E

(a)

To determine

To graph: The equation p=vw .

(a)

Expert Solution

Answer to Problem 46E

The graph

Explanation of Solution

Given information: Music: The frequency of a sound wave is called its pitch. The pitch p of a musical tone and its wavelength w are related by the equation p=vw, where v is the velocity of sound through air. Suppose a sound wave has a velocity of 1056 feet per second.

Calculation:

p=10562

Advanced Mathematical Concepts: Precalculus with Applications, Student Edition, Chapter 4.7, Problem 46E

(b)

To determine

What lines are close to the maximum values for the pitch and the wavelength?

(b)

Expert Solution

Answer to Problem 46E

Both axis are close

Explanation of Solution

Calculation:

Both axis are close

(c)

To determine

What happens to the pitch of the tone as the wavelength decreases?

(c)

Expert Solution

Answer to Problem 46E

As the wavelength decreases the pitch increases

Explanation of Solution

Calculation:

The graph represents an inverse variation.

As one value increases the other decreases and

As the wavelength decreases the pitch increases.

(d)

To determine

What happens to the pitch of the tone if the wavelength is doubled?

(d)

Expert Solution

Answer to Problem 46E

If we double the wavelength then the pitch is halved

Explanation of Solution

Calculation:

The opposite reaction

If you double the wavelength,

Then the pitch is halved.

Chapter 4.7, Problem 45E

Chapter 4.7, Problem 47E

Chapter 4 Solutions

Advanced Mathematical Concepts: Precalculus with Applications, Student Edition

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To graph: The equation p = v w .

Concept explainers

Videos

To graph: The equation p=vw .

Answer to Problem 46E

Explanation of Solution

What lines are close to the maximum values for the pitch and the wavelength?

Answer to Problem 46E

Explanation of Solution

What happens to the pitch of the tone as the wavelength decreases?

Answer to Problem 46E

Explanation of Solution

What happens to the pitch of the tone if the wavelength is doubled?

Answer to Problem 46E

Explanation of Solution

Chapter 4 Solutions

Additional Math Textbook Solutions