Chapter 47, Problem 2Q

Give the structure of S-carvoneand explain how will you identify the compound once the IR spectra is registered ?

Analyze the spectral data for 4-cyclohexene-cis-1,2-dicarboxylic acid  1. Assign the peaks in the region above 1600 cm-1 of the IR. 2. In the 1H NMR spectrum, assign the various resonances to the hydrogen nuclei responsible for them.  3. What should the integral be for the peak at 12.25 ppm?  4. Write the 1H NMR spectral information in ACS format. 5. For the 13C NMR data, assign the resonances to the carbon nuclei responsible for them. 6. Can you tell whether you have the cis or trans 4-cyclohexene-1,2-dicarboxylic acid based on the number of signals seen on 13C NMR? Why or why not?

Identify the IR Spectra for 1-Bromo-2-Hexene.

Give and observation and inference when the compound hexane is subjected into test for Br2 in CCl4

Which compound(s) in spearmint oil do you expect will be visible on the TLC plate under UV irradiation? Explain why. Compounds:R-carvone, R-limonene and (1R,2R,4R)-dihydrocarveol

What are the limitations and advantages of Nera-IR spectrometry regarding the functional groups that can be studied in this region.

for the mass spectrum of glycerol explain and interpret the spectra below give atleast 5 fragmentation pattern

Sketch the spectra that would be obtained for 2-chloroethanol: The 1H NMR spectrum for an anhydrous sample of the alcohol.

This is an illustration of TLC plates. The compounds used were syn-azobenzene (A) and anti-azobenzene (B). The difference between the two plates are that the first was placed in 15% methylene chloride in pet. ether and the second was placed in 30% methylene chloride in pet. ether. I calculated Rf values to be 0.47 mm for syn-azobenzene and 0.44 mm for anti-azobenzene in 15% while syn-azobenze had a Rf of 0.28 mm and 0.16 mm. Which solvent is best at separating and how does Rf help identify which isomer is which? I read that the anti is supposed to have a higher Rf but that is not the case here so I want to know if the syn is supposed to have the higher Rf and the anti is supposed to have the lower one.