Chapter 5, Problem 27P

According to Planck’s law of black- body radiation, the spectral energy density R as a function of wavelength ? (m) and temperature T(K) is given by:

$R=\frac{2\pi c^{2}h}{{\lambda }^5}\frac{1}{e^{hc/\lambda kT}-1}$

where $c=3\times {10}^8$ m/s is the speed of light, $h=6.626\times {10}^{-34}$ J-s is the Planck constant, and $k=1.38\times {10}^{-23}$ J/K is Boltzmann constant. Make the shown figure that contains plots of R as a function of ? for $0.1\le \lambda \le 3$ µm for three temperatures T=3,000 K, T=4,000 K. and T=5,000 K.