Chemistry: The Central Science, Books a la Carte Edition & Solutions to Red Exercises for Chemistry & Mastering Chemistry with Pearson eText -- Access Card  Package
Chemistry: The Central Science, Books a la Carte Edition & Solutions to Red Exercises for Chemistry & Mastering Chemistry with Pearson eText -- Access Card Package
1st Edition
ISBN: 9780134024516
Author: Theodore E. Brown, H. Eugene LeMay, Bruce E. Bursten, Catherine Murphy, Patrick Woodward, Matthew E. Stoltzfus
Publisher: PEARSON
bartleby

Videos

Question
Book Icon
Chapter 5, Problem 31E

(a)

Interpretation Introduction

To determine: The Lewis structure of CS2 molecule; also the way to predict its bond order of CS bond.

Solution: The Lewis structure of CS2 is drawn. The bond order is determined by calculating the number of bonds between carbon and oxygen atoms in the Lewis structure.

Explanation:

The Lewis structure for a given compound is the representation of bonding and non bonding electron pairs in a molecule. The Lewis structure represents the number of single bonds and double bonds in the molecule along with the lone pair of electrons.
The electronic configuration of C and S is,

    C=1s22s22p2S=1s22s22p63s23p4

Since, carbon atom has two electrons in its p orbital, it can accept four more electrons and sulphur atom contains four atoms in its p orbital, it can accept two more electrons. Therefore, the carbon atoms makes double bond with two sulphur atoms to satisfy its valancy.
The Lewis structure of CS2 molecule is,

Chemistry: The Central Science, Books a la Carte Edition & Solutions to Red Exercises for Chemistry & Mastering Chemistry with Pearson eText -- Access Card  Package, Chapter 5, Problem 31E

Figure 1


The bond order is defined as the number of bonds between two atoms in a molecule. It is determined by the Lewis structure of the molecules. The number of bonds between carbon and sulphur in its structure are 2. Therefore, the bond order of CS bond in CS2 molecule is 2.

Conclusion:

The Lewis structure of CS2 is drawn. The bond order is determined by calculating the number of bonds between carbon and oxygen atoms in the Lewis structure

(b)

Interpretation Introduction

To determine: The structure of CS2 molecule by using the VSEPR method.

(c)

Interpretation Introduction

To determine: The balanced chemical equation for the given reaction.

(d)

Interpretation Introduction

To determine: The values of ΔH0 and ΔG0 for the given reaction; If the reaction is exothermic and spontaneous or not.

(e)

Interpretation Introduction

To determine: The value of ΔS0 for the vaporization of CS2(l) ; if the sign of ΔS0 favors vaporization or not.

(f)

Interpretation Introduction

To determine: The boiling point of CS2(l) ; if the CS2 a liquid or gas at 298K and 1atm .

Blurred answer

Chapter 5 Solutions

Chemistry: The Central Science, Books a la Carte Edition & Solutions to Red Exercises for Chemistry & Mastering Chemistry with Pearson eText -- Access Card Package

Ch. 5.5 - Practice Exercise 1 Suppose you have equal masses...Ch. 5.5 - Prob. 5.6.2PECh. 5.5 - Prob. 5.7.1PECh. 5.5 - Prob. 5.7.2PECh. 5.6 - Prob. 5.8.1PECh. 5.6 - Prob. 5.8.2PECh. 5.6 - Prob. 5.9.1PECh. 5.6 - Prob. 5.9.2PECh. 5.7 - Prob. 5.10.1PECh. 5.7 - Prob. 5.10.2PECh. 5.7 - Prob. 5.11.1PECh. 5.7 - Prob. 5.11.2PECh. 5.7 - Prob. 5.12.1PECh. 5.7 - Practice Exercise 2 Use Table 5.3 to calculate the...Ch. 5.8 - Prob. 5.13.1PECh. 5.8 - Practice Exercise 2 Given the following standard...Ch. 5.8 - Prob. 5.14.1PECh. 5.8 - Prob. 5.14.2PECh. 5 - Prob. 1DECh. 5 - Prob. 1ECh. 5 - Prob. 2ECh. 5 - Prob. 3ECh. 5 - Practice Exercise 2 Using Table 20.1, rank...Ch. 5 - Prob. 5ECh. 5 - Prob. 6ECh. 5 - Prob. 7ECh. 5 - Prob. 8ECh. 5 - Prob. 9ECh. 5 - Prob. 10ECh. 5 - Prob. 11ECh. 5 - Prob. 12ECh. 5 - Prob. 13ECh. 5 - Prob. 14ECh. 5 - Prob. 15ECh. 5 - Prob. 16ECh. 5 - Prob. 17ECh. 5 - Prob. 18ECh. 5 - Prob. 19ECh. 5 - Prob. 20ECh. 5 - Prob. 21ECh. 5 - Prob. 22ECh. 5 - Prob. 23ECh. 5 - Prob. 24ECh. 5 - Prob. 25ECh. 5 - Prob. 26ECh. 5 - Prob. 27ECh. 5 - In chemical kinetics, the entropy of activation is...Ch. 5 - Prob. 29ECh. 5 - Prob. 30ECh. 5 - Prob. 31ECh. 5 - The following data compare the standard enthalpies...Ch. 5 - Prob. 33ECh. 5 - Prob. 34ECh. 5 - Prob. 35ECh. 5 - What is the reducing agent in the following...Ch. 5 - Prob. 37ECh. 5 - Prob. 38ECh. 5 - Prob. 39ECh. 5 - Prob. 40ECh. 5 - Prob. 41ECh. 5 - Prob. 42ECh. 5 - Prob. 43ECh. 5 - The standard cell potential is 1.46 V for a...Ch. 5 - Prob. 45ECh. 5 - Prob. 46ECh. 5 - Prob. 47ECh. 5 - Prob. 48ECh. 5 - Prob. 49ECh. 5 - Practice Exercise 1 Which of the following...Ch. 5 - Prob. 51ECh. 5 - Prob. 52ECh. 5 - Prob. 53ECh. 5 - Prob. 54ECh. 5 - Prob. 55ECh. 5 - Prob. 56ECh. 5 - Prob. 57ECh. 5 - Prob. 58ECh. 5 - Prob. 59ECh. 5 - Prob. 60ECh. 5 - What is the connection between Hess’s law and the...Ch. 5 - Prob. 62ECh. 5 - 20.2 You may have heard that “antioxidants” are...Ch. 5 - Prob. 64ECh. 5 - Prob. 65ECh. 5 - Prob. 66ECh. 5 - Prob. 67ECh. 5 - Prob. 68ECh. 5 - Prob. 69ECh. 5 - Prob. 70ECh. 5 - Prob. 71ECh. 5 - Prob. 72ECh. 5 - 20.13 What is meant by the term oxidation? On...Ch. 5 - Prob. 74ECh. 5 - Prob. 75ECh. 5 - Prob. 76ECh. 5 - Prob. 77ECh. 5 - Prob. 78ECh. 5 - Prob. 79ECh. 5 - Prob. 80ECh. 5 - Prob. 81ECh. 5 - Prob. 82ECh. 5 - Prob. 83ECh. 5 - Prob. 84ECh. 5 - Prob. 85ECh. 5 - The heat of combustion of ethanol, C2H5OH(l) is...Ch. 5 - Prob. 87ECh. 5 - Prob. 88ECh. 5 - Prob. 89ECh. 5 - The automobile fuel called E85 consists of 85%...Ch. 5 - Prob. 91AECh. 5 - Prob. 92AECh. 5 - Prob. 93AECh. 5 - Prob. 94AECh. 5 - 5.95 Consider a system consisting of the following...Ch. 5 - A sample of gas is contained in a...Ch. 5 - Prob. 97AECh. 5 - Prob. 98AECh. 5 - A house is designed to have passive solar energy...Ch. 5 - Prob. 100AECh. 5 - Prob. 101AECh. 5 - Prob. 102AECh. 5 - Burning methane in oxygen can produce three...Ch. 5 - Prob. 104AECh. 5 - Prob. 105AECh. 5 - The hydrocarbons acetylene (C2H2) and benzene...Ch. 5 - Prob. 107AECh. 5 - Three common hydrocarbons that contain four...Ch. 5 - Prob. 109AECh. 5 - The Sun supplies about 1.0 kilowatt of energy for...Ch. 5 - It is estimated that the net amount of carbon...Ch. 5 - Prob. 112IECh. 5 - Prob. 113IECh. 5 - Prob. 114IECh. 5 - Prob. 115IECh. 5 - Prob. 116IECh. 5 - Prob. 117IECh. 5 - The methane molecule, CH4, has the geometry shown...Ch. 5 - Prob. 119IE
Knowledge Booster
Background pattern image
Chemistry
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Recommended textbooks for you
Text book image
Chemistry
Chemistry
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Cengage Learning
Text book image
Chemistry
Chemistry
ISBN:9781259911156
Author:Raymond Chang Dr., Jason Overby Professor
Publisher:McGraw-Hill Education
Text book image
Principles of Instrumental Analysis
Chemistry
ISBN:9781305577213
Author:Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:Cengage Learning
Text book image
Organic Chemistry
Chemistry
ISBN:9780078021558
Author:Janice Gorzynski Smith Dr.
Publisher:McGraw-Hill Education
Text book image
Chemistry: Principles and Reactions
Chemistry
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:Cengage Learning
Text book image
Elementary Principles of Chemical Processes, Bind...
Chemistry
ISBN:9781118431221
Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. Bullard
Publisher:WILEY
The Laws of Thermodynamics, Entropy, and Gibbs Free Energy; Author: Professor Dave Explains;https://www.youtube.com/watch?v=8N1BxHgsoOw;License: Standard YouTube License, CC-BY