PRINCIPLES OF GEOTECH.ENGINEERING >LL+M
9th Edition
ISBN: 9781337583879
Author: Das
Publisher: CENGAGE L
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Chapter 5, Problem 5.10P
To determine
Classify the soil according to the Unified soil classification system and provide group symbol and group name.
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A soil sample is oven-dried from its liquid limit state to its dry state causing a volume change of 60% of the dry volume. Likewise, the
same soil is oven-dried from its plastic limit state to its dry state causing a volume change of 20% of the dry volume. The liquid limit
and plastic limit are 54% and 26%, respectively. Determine the specific gravity of soil solids, shrinkage limit and shrinkage ratio.
1. INPUT THE VALUE OF SPECIFIC GRAVITY OF SOIL SOLIDS IN 2 DECIMAL PLACES
2. INPUT THE VALUE OF SHRINKAGE LIMIT IN PERCENTAGE FORM AND IN 2 DECIMAL PLACES
3. INPUT THE VALUE OF SHRINKAGE RATIO IN 2 DECIMAL PLACES
Answer with text and/or attachments:
Let us assume that a soil sample taken in the field is taken and it must be identified by the SUCS Method and AASHTO Method.
Moisture content = 5.75%
Limit liquid = 53.5
Plastic limit = 31.6
Granulometry
Sieve % Pass
No. 4 100
# 40 68
# 200 54.3
Do you select the best answer?
a) Inorganic silt and sand, with low plasticity
b) Inorganic clay with low plasticity
c) Clay silt, traces of gravel, dark Brown
(c) A sample of clay having a mass of 675 gm was coated with paraffin wax. The combined mass of the
clay and the wax was found to be 682 gm. The volume was found by immersion in water as 345 ml.
The sample was then broken to open. The water content and specific gravity of solids were found to
be 15 % and 2.70 respectively. Calculate the bulk density of soil, its void ratio, and degree of
saturation. Take specific gravity of wax as 0.89.
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- U B. ( A Soil Specimen has the following characteristics: % passing No.4 sieve = 85 % passing No.200 sieve = 11 D60 = 2 mm D30 = 0.35 mm D₁0 = 70 μm L.L = 36% P.L = 31% D8 = 2 µm 1. Classify the specimen according to the Unified Soil Classification System (USCS). Assign the group name and the group symbol. 2. Determine the soil activity. 3. Determine the soil Liquidity index and consistency index if we = 26%.arrow_forwardfind the following: a. What is the value of the percent passing for sieve with 2 mm. opening in percentage? b. What is the value of the percent passing for sieve with 150 μm. opening in percentage? c. What is the value of the Effective Size of soil in mm.? d. What is the value of the coefficient of gradation?e.What is the value of the coefficient of uniformity? f. What are the percentages of gravel, sand, and Fines using the limits indicated by USCS? g. What are the percentages of gravel, sand, silt and clay using the limits indicated by MIT? h. What are the percentages of gravel, sand, silt and clay using the limits indicated by AASHTO? i. What are the percentages of gravel, sand, silt and clay using the limits indicated by USDA?arrow_forwardA soil sample is subjected to laboratory sieve analysis using a complete set of standard IS sieves. Out of 2 kg of soil used in the test, 800 gram was retained on IS 600 micron sieve, 1000 gram was retained on IS 500 micron sieve and the remaining 200 gram was retained on IS 425 micron sieve. The uniformity co-efficient for the soil is: 1.1.2 X2. 0.833 X3. 1.412 X4.0.71 Сол Дво Dio Que Chosarrow_forward
- Sr B. ( A Soil Specimen has the following characteristics: % passing No.4 sieve = 85 % passing No.200 sieve = 11 D60 = 2 mm D30=0.35 mm D₁0 = 70 μm D8=2 μm L.L = 36% P.L = 31% 1. Classify the specimen according to the Unified Soil Classification System (USCS). Assign the group name and the group symbol. 2. Determine the soil activity. 3. Determine the soil Liquidity index and consistency index if wc = 26%.arrow_forwardA soil is mixed at a water content of 16% and compacted in a 1000 ml cylindrical mold. The sample extruded from the mold has a mass of 1620 g, and the specific gravity of the soil grains is 2.69. Find the following: a. void ratio, b. degree of saturation, and c. dry unit weight of the compacted sample. d. If the sample is soaked in water at the same void ratio, what would be the new water content?arrow_forwardGEOTECHNICAL ENGINEERING A soil sample is oven-dried from its liquid limit state to its dry state causing a volume change of 19.68% of the dry volume. Likewise, the same soil is oven-dried from its plastic limit state to its dry state causing a volume change of 8% of the dry volume. The liquid limit and plastic limit are 60.54% and 50.37%, respectively. Determine the specific gravity of soil solids, shrinkage limit and shrinkage ratio.arrow_forward
- PROBLEM No. 6 Atterberg Limit From the laboratory results of the Atterberg Limit Test, the Liquid Limit of the soil is 65% and the Plastic Limit of the soil is 40%. a. Determine the Plasticity Index. b. If the in-situ moisture content of the soil is 85%, determine the Liquidity Index of the soil. c. Determine the state of consistency of the in-situ soil. d. Determine the Consistency Index of the soil.arrow_forwardA sample of soil was tested in the laboratory, and the test results were listed as follows. Classify the soil by Unified Soil Classification System. 1. Liquid limit = 29%. 2. Plastic limit = 19%. 3. Mechanical grain-size analysis:arrow_forwardb. Compute the plastic limit. C. Compute the natural water content. d. Compute the plasticity index. e. Compute the liquidity index. f. Compute the consistency index. PROBLEM NO. 4 From the table shows a summary of a liquid limit and plastic limit test. LIQUID LIMIT TEST Soil Wt. of wet Wt. of dry Water No. of Sample Soil (kg) Soil (kg) A. Content Blows 9.5 6.7 28 B 7.95 5.54 20 8.21 5.69 18 D. 12.85 8.83 13 PLASTIC LIMIT TEST Wt. of Dry Soil(kg) Soil Wt, of Wet Sample Soil(kg) 9.05 7.35 2 8.66 7.01 Natural Water Content Scil Wt. of Wt. of Sample Wet Soil Dry Soi! 1 9.69 7.0 9.47 6.86 a. Compute the liquid limit. b. Compute the plastic limit. C. Compute the natural water content. d. Compute the plasticity index. e. Compute the liquidity index GEOTECHNICAL ENGINEERING 1arrow_forward
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